Answer:
Given,
n = 390
p = 0.288
Mean = np
= 390*0.288
= 112.32
Standard deviation = sqrt(npq)
substitute values
= sqrt(390*0.288*(1-0.288))
= 8.94
P(X >= 115) = 1 - P(X < 115)
= 1 - P(z < (115 - 112.32)/8.94)
= 1 - P(z < 0.2998)
= 1 - 0.6178351 [since from z table]
= 0.3821649
= 0.3822
P(X >= 115) = 0.3822
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