Question

Freckles are caused by a dominant allele. A man has freckles but one of his parents does not have freckles. The man has fathered a child with a woman that does not have freckles. Draw out a pedigree with the genotypes of grandparents and parents (use “_” when one allele is unknown) (1 point) What is the probability that their child has freckles?

Answer 1

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Let the domenant allele de represened by Fand. recesine by s. (ta freckles). The parent of the man does not have reches. Sot, that parents genotipfe must be sh since not hang pecktes in nassine do due parent of the man has freckles. so, dus genotype nay be FL or ff since fu dominant). So, let us bresent that parents genotype by El.

Now, the man has fuckles. So, chis genotype may be FF or th. He must have got one allele from ane parent and one from olher. So he must have ane lgene. One parent is lef and can give hem only type allele). So, the man's genotype is 1 The moman So her Pelique - he marruns also densul have wekeles genotype must be ff. Old-brandparents u o - parents FA Man u male s Woman simale male I 0 affected I sex unspeeissed unaffected male. tross → Man ferched) Wanan (normal)

I gamites Ofeping dt. Not preckled- So Freckled out of 2 freckles I children, and to probability of - 50% child child will having have fuckles =