6Homework Answers
50% percent penetrance means that half of the populations with the heterozygous condition will get the disease even if the mutation is dominant.
Let's make a punnet square with a father of genotype Aa and Mother, aa.
| a | a | |
| A | Aa | Aa |
| a | aa | aa |
From the above cross
The probability of showing normal phenotype = 3/4 (2 from aa and 1/2 from Aa as 50% penetrance is there)
The probability of having two children with normal phenotype = 3/4*3/4= 9/16
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