Question

1 60 120 180 240 300 360 Torsion angle (degrees) AE (kcal/mol)In the box below each molecule, draw Newman projections for the structures A, B, and C shown from the perspective indicated.

I already know how to do 1 and 2. if you could show me how to do number 3 on the graph above, and how to calculate the expected energy of the conformer please

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Answer #1

Expected energies :

CH3-CH3 eclipsed=3.4kcal/mol

H-H eclipsed=1kcal/mol

CH3-H eclipsed=1.4 kcalmol

CH3-CH3 gauche interaction=0.9 kcal/mol

using above values this problem can be solved.please find the attached image.(HH) 1 kcal/mol (CH) 1-4 60 A # canada Cld. યo *2 + H 150 Cup 70 60.34 w 4.4 Koolitan a kcal/mol F gauche E - +1473-4-5-8k co67 68 kcal/mol 5.8 kcal/mol 5.8kal/mol 4.2 peal mot Orckealmon Sxcalfoo doo og kal/mol 1.0.9 kcal mo) do 60 120 180° 2400 200

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