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Engineers concerned about a tower's stability have done extensive studies of its increasing tilt. Measurements of...

Engineers concerned about a tower's stability have done extensive studies of its increasing tilt. Measurements of the lean of the tower over time provide much useful information. The following table gives measurements for the years 1975 to 1987. The variable "lean" represents the difference between where a point on the tower would be if the tower were straight and where it actually is. The data are coded as tenths of a millimeter in excess of 2.9 meters, so that the 1975 lean, which was 2.9646 meters, appears in the table as 646. Only the last two digits of the year were entered into the computer.

Year 75 76 77 78 79 80 81 82 83 84 85 86 87
Lean 646 648 659 671 677 691 700 701 717 721 728 746 761

(a) Plot the data. Consider whether or not the trend in lean over time appears to be linear. (Do this on paper. Your instructor may ask you to turn in this graph.)

(b) What is the equation of the least-squares line? (Round your answers to three decimal places.)
y =  +  x

What percent of the variation in lean is explained by this line? (Round your answer to one decimal place.)
%

(c) Give a 99% confidence interval for the average rate of change (tenths of a millimeter per year) of the lean. (Round your answers to two decimal places.)
(  ,

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Answer #1

In Excel

data -> data analysis -> regression

M F F G H K. N y 75 646 X Regression 76 648 Input 77 659 OK Input Y Range: SFS1:SFS14 78 671 Cancel Input X Range: SES1:SES14

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.9934
R Square 0.9869
Adjusted R Square 0.9857
Standard Error 4.3755
Observations 13
ANOVA
df SS MS F Significance F
Regression 1 15804.4835 15804.4835 825.5212 0.0000
Residual 11 210.5934 19.1449
Total 12 16015.0769
Coefficients Standard Error t Stat P-value Lower 95%
Intercept -57.4286 26.2989 -2.1837 0.0515 -115.3121
x 9.3187 0.3243 28.7319 0.0000 8.6048

a)

780 760 740 720 700 680 660 640 74 76 78 80 82 84 86 88

b)

y^= -57.429 + 9.319 x

% of variation explained = R^2 = 0.987 = 98.7 %

c)

99% confidence interval for slope = (8.311,10.326)

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