Question

pls help

Write a method void remove(int *a, int index) that will remove the number at the
given index and shift all remaining numbers one position to the left in the array a. Assume
1that the last element of the array is -1. Now, write a main function that will define an array
int A[40]=[3, 5, 9, 17, 24, -1]; read from user input an index; and call the method
remove passing array A and the index given by the user. For example if user enters 2, then
number 9 at index 2 will be removed and the array will now contain [3, 5, 17, 24, -1]
Print the array after the removal. You MUST write the remove method using ONLY pointers
and pointer arithmetic (no array notation [ ] allowed).

Answer 1

code in c

#include<stdio.h>

void remove1(int *, int );

void main()

{

int A[40]={3,5,9,17,24,-1};

int index;

printf("Please enter the valid index :");

scanf("%d",&index);

remove1(A,index);

}

void remove1(int *a, int index)//remoe1 function

{

int i,n=0;//variables n used for finding the length of the array

for(i=0;a[i]!='\0';i++)

n++;

for (i = index; i < n - 1; i++)//then from the next element from the indexed element

{

a[i] = a[i + 1];

}

//prints the resultant array.

printf("The resultant array is is \n");

for (i = 0; i < n - 1; i++)

{

printf("%d\n", a[i]);

}

}

output

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