2 NO2 (g) = N2(g) + 2 O2(g). ∆H = -67.6 KJ
∆H(O2) = 0
∆H(N2) = 0
∆H(reaction) = ∆H(N2) + 2 * ∆H(O2) - 2* ∆H(NO2)
= -67.6 = 0 + 2*0 - 2*(NO2)
NO2 = 33.8 KJ / mol
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