If an AC induction motor says in nameplate that the power is 100 HP, and it has an efficiency of 88%. It is operating at a 90% of full load. What is the input kW to the motor?
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Output power rated is 100 HP
its working on 90% of full load.
so output power currently is 90% of 100 HP which is 90HP.
As 1 HP = 746 watts
Efficiency = 0.88 or 88%
Efficiency = Output Power / Input Power
Input power = Output Power / Efficiency
Input power = (90*746)/0.88
Input power = 76295.45 watt or 76.295 kW.
If an AC induction motor says in nameplate that the power is 100 HP, and it...
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