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If an AC induction motor says in nameplate that the power is 100 HP, and it...

If an AC induction motor says in nameplate that the power is 100 HP, and it has an efficiency of 88%.  It is operating at a 90% of full load.  What is the input kW to the motor?

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Answer #1

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Output power rated is 100 HP

its working on 90% of full load.

so output power currently is 90% of 100 HP which is 90HP.

As 1 HP = 746 watts

Efficiency = 0.88 or 88%

Efficiency = Output Power / Input Power

Input power = Output Power / Efficiency

Input power = (90*746)/0.88

​​​​​​Input power = 76295.45 watt or 76.295 kW.

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