Question

(1 point) (Note: This problem has several parts. The latter parts will not appear until after the earlier parts are completed correctly.) Graph and shade the points (if any) that satisfy the following system of linear inequalities. Then find the coordinates of all of the corner points: 2x - 7y 10x + 3y 2x - 8y 10x + 4y 2 = < -38, -38, 44, 44 Which one of the following statements best describes your solution: A. There are no corner points, because there are no points that satisfy all of the inequalities. B. There are no corner points, because the shaded points constitute a single half-plane. C. There is exactly one corner point. D. There are exactly two corner points. E. There are exactly three corner points. F. There are exactly four corner points. G. There are exactly five corner points. H. There are more than five corner points. Statement: F Yes, that is correct. What are the corner points? Beginning with the corner point in the first quadrant and then proceeding around the boundary in counter-clockwise order, enter the coordinates of the corner points: Corner in first quadrant:( Corner in second quadrant:( Corner in the third quadrant:( Corner in fourth quadrant:(

Answer 1

Consider Given inequality as Equality 2x - 74 -= -38 1021 +34 = -38 x - y = 22 . 50+2y=22 Il _X-aris- y-4245 point intersecting with Co- orclincue axes line 4 line ₂ line L₂ line Ly (-19,0) (-38%10) (22,0) (410) (0, 3) (e,3%) to, 1/2) to )

Goaph 1 y-onus Pago No. Date:__ 2022°) x-arus L (0,-3872) -16+ For corner point solving (41 and 12 we get C 6 and 7 we get L2 and 12 we get - 62 and 4 we get (-5, 4) =B 12, 6) = A. 62-6)=0 16,-4)=D point which satisfy sheaded - all Answer P F region shows inequality There are enactly fom corner points Correr point in Corner point in corner point in corner point in first second third fourth quadrant quadoon quadsunt quad sant = = = ( 2 6 ) (-5,4) (-2,-6)