Solution
Option b is correct.
The exact shape of t distribution depends on the degrees of freedom. If n is small , the curve is more spread out in the tails and flatter around the centre.As n increases , t distribution tends to normal distribution .
The shape of chi-square curve depends on the value of n . For small n , the curve is positively skewed.As n increases chi - square is approximately normally distributed.
The shape of F curve depends on degrees of freedom
( m, n).When one or both parameters increase the F distribution tends to become more and more symmetrical.
Only normal distibution is independent of degrees of freedom. ie, its shape does not change according to degrees of freedom or sample size. For any value of degrees of freedom, normal distribution is a bell shaped curve.
QUESTION 12 Which of the following distribution's shape does not change with degrees of freedom? a....
The shape of which distribution is not controlled by the degrees of freedom? F t Which of the following accurately represents characteristics of the x2 distribution? There may be more than one correct answer, select all that are correct. The degrees of freedom for a Chi-square test of independence are k-1. As the degrees of freedom increase, the critical value of the chi-square distribution becomes larger. | It can assume both negative and positive values. The Chi-square goodness-of-fit test is...
a) true b) false 42. For a chi-square distributed random variable with 10 degrees of freedom and a level of sigpificanoe computed value of the test statistics is 16.857. This will lead us to reject the null hypothesis. a) true b) false 43. A chi-square goodness-of-fit test is always conducted as: a. a lower-tail test b. an upper-tail test d. either a lower tail or upper tail test e. a two-tail test 44. A left-tailed area in the chi-square distribution...
3. If a random variable Y has a Chi-square distribution with 9 degrees of freedom. a) The mean of the distribution is b) The standard deviation of the distribution is c) The probability, p( y = 5) = d) The probability, P(Y>8 ) = e) the probability, p( y < 2) = _
For a chi-square test of independence, we calculate the degrees of freedom using which formula? A. ??=???? × ??????? B. ??=???? + ??????? C. ??=(????−1)×(???????−1) D. ??=(????−1)+(???????−1)
QUESTION 7 In which of the following problems, would using degrees of freedom be necessary? a. distribution, n = 35 Ob.& distribution, o = 36.7, n = 50 OC. & distribution, s = 8.4, n = 32 d.x distribution, o = 12.1, n = 25
QUESTION 1 For the t distribution with 11 degrees of freedom, find the value for which the upper tail area is 0.25. QUESTION 2 For the t distribution with 17 degrees of freedom, calculate P(T<2.11).
The Chi-Square Table (Chapter 17) The chi-square table: The degrees of freedom for a given test are listed in the column to the far left; the level of significance is listed in the top row to the right. These are the only two values you need to find the critical values for a chi-square test. Increasing k and a in the chi-square table Record the critical values for a chi-square test, given the following values for k at each level...
Consider a Chi-square random variable with 15 degrees of freedom and 0.1 level of significance. Which of the following test statistic values will result in rejection of the null hypothesis? (1) 21.1. (2) 18.5. (3) 19.8. (4) 23.5. (5) 2.7.
When Chi-square distribution is used as a test of independence, the number of degrees of freedom is related to both the number of rows and the number of columns in the contingency table. Select one: True False Question 2 Answer saved Points out of 1.000 Flag question Question text A goodness of fit test can be used to determine if membership in categories of one variable is different as a function of membership in the categories of a second variable...
proof for distribution of (n-1)S^2/sigma^2 is the chi square distribution with n-1 degrees of freedom. I don't understand the expansion of the square, specifically how certain terms disappeared and how a sqrt(n) appeared. Also towards the end, why does V have a degree of freedom of 1? x A detailed explanation of what happened from step 2 to step 3 would be very helpful! THEOREM B The distribution of (n − 1)S2/02 is the chi-square distribution with n – 1...