Question

Done Car Value Dataset age price 6 8052.7 4.6 8838.25 2. 9 11535.8 4.2 9936.56 9.2 6744.53 2.3 12867.39 9 5952.4 4 9426.85 3.2 10764.8 6.8 6965.94 7.6 7225.59 1.6 16292.48 10.3 6358.96 6.8 7245.94 4.6 9032.25 10.4 5302.26 2.1 13414.57 9.6 5537.57 9.2 6719.53 8.7 5958.5 2.3 12732.39 8.8 5943.07 9.3 6709.59 10.6 5784.29 4.7 8570.02 5 9088.46 2.7 12813.1 5 9323.46 3.2 10816.8 8.6 6046.68

Answer 1

1.) Average age= [6+ 4.6+2.9 +4.2+9.2+2.3+9+4+3.2+6.8+7.6+1.6+10.3+6.8+4.6+10.4+2.1+9.6+9.2+8.7+2.3+8.8+9.3+10.6+4.7+5+

2.7+5+3.2+8.6]/30=6.11

Average price of sample = [8052.7+8838.25+11535.8+9936.56+6744.53+12867.39+5952.4+9426.85+10764.8+6965.94+7225.59+16292.48+6358.96+7245.94+9032.25+5302.26+13414.57+5537.57+6719.53+5958.5+12732.39+ 5943.07+6709.59+5784.29+8570.02+9088.46+12813.1+9323.46+10816.8+6046.68]\30

=8733.35

2.) Standard deviation of age =√ (1/30×standard deviation ²)-mean^​​2

^{=√45.688-37.3321=√8.3559=2.8906}

^{Standard deviation of price of sample =√(84090508.19-76271402.22)=2796.266}

^{​​​​​​4.)a.) a is here constant. To linearise the above equation we use a and k.}

^{b.)k is also here constant.}