Question

Find interquartile range Find the mean deviation from the mean and median Min Max No. of...

Find interquartile range Find the mean deviation from the mean and median

Min Max No. of people

1000 2000 28

2000 3000 52

3000 4000 45

4000 5000 35

5000 6000 63

6000 7000 130

7000 8000 110

8000 9000 62

9000 10000 55

10000 11000 38

11000 12000 35

12000 13000 50

13000 14000 55

14000 15000 88

15000 16000 60

16000 17000 35

17000 18000 30

18000 19000 22

19000 20000 7

0 0
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Answer #1

Here, n 1000 01 class Class withvalue of the observation in cfcolumn am ( 9 1000 h -value of the observation in cf column 4Here, n 1000 3 class Class withvalue of the observation in cfcolumn 3 1000 th -value of the observation in cfcolumn - (750) vΣ 9574000 Mean x = 9574 1000 Class Mid value (r) r9574 1000 2000 2000 3000 3000 4000 4000 5000 5000 6000 6000 7000 7000 8000Class cfMid value (x) x -M- x - 8596.7742 28 80 125 160 63 223 353 7000 8000110 463 525 580 618 653 703 13000 14000 55758 846To find Median Class 6) value of observation 1000 th value ofobservation - value of 500h observation From the column of cumul

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