Applying conservation of momentum
=> Initial momentum of system = 200 * 0.95c * 1/sqrt( 1 - 0.952)
= 608.486c kg-m/sec
=> 608.486c = (200 + 100) * v * 1/sqrt( 1 - v2/c2)
=> v = 0.897c
=> speed of combined mass = 0.897c
A 200 kg mass with speed 0.950 c collides and sticks with a 100 kg mass...
An air-track cart with mass m1=0.30kg and initial speed v0=0.95m/s collides with and sticks to a second cart that is at rest initially. If the mass of the second cart is m2=0.50kg, how much kinetic energy is lost as a result of the collision?
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only need part c
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