Please explain in written format and EXCEL function.
A statistics instructor believes that fewer than 20% of students at a local college attended the premiere showing of the latest Harry Potter movie. She surveys 84 of her students and finds that 11 of them attended the midnight showing.
At a 1% level of significance, an appropriate conclusion is
Solution:
The provided information: number of favorable cases = x = 11 and
the sample size is n = 84.
So, Sample proportion = x / n = 11 / 84 = 0.131
(1) Null and Alternative Hypotheses:
The following null and alternative hypotheses need to be
tested:
Ho: p = 0.2
Ha: p < 0.2
This corresponds to a Left tail test, for which a z-test for one
proportion will be used.
(2) Rejection Region:
Given significance level = α = 0.01
So Critical Value for the test is, Zc = -2.33 .....Using excel
formula
=NORMSINV(0.01)
(3) Test statistic:
(4). Decision: Since it is observed that |z| = 1.5821 ≤ Zc =
2.33
It is then concluded that the Null Hypothesis is not
rejected.
(5). Conclusion: It is concluded that the Null Hypothesis is not
rejected. Therefore, there is not enough evidence to claim that the
population proportion p is Less than 0.2, at the 0.01 significance
level.
That is, Insufficient evidence to accept the claim (conclude) that the percentage of students who attended the midnight showing of Harry Potter is less than 20%.
Hence option a is correct.
Done
Please explain in written format and EXCEL function. A statistics instructor believes that fewer than 20%...
A statistics instructor believes that more than 20% of Evergreen Valley College (EVC) students attended the midnight showing on opening night of the latest Harry Potter movie. She surveys 84 of her students and finds that 11 attended the midnight showing. What is an appropriate alternative hypothesis? p ≤ 0.20 p = 0.20 p < 0.20 p > 0.20
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