Question

Problem 6.14 Humidity and Condensation Air at 30.0% relative humidity is cooled isobarically at 1 atm absolute from 90.0°C to 35.0°C. a. Estimate the dew point and the degrees of superheat of the air at 90.0°C. Dew point: Degrees of superheat: doc b. How much water condenses (mol) per cubic meter of feed gas? (See Example 6.3-2) mol c. Suppose a sample of the 90.0°C air is put in a closed variable-volume chamber containing a mirror and the pressure is raised at constant temperature until a mist forms on the mirror. At what pressure (atm) would the mist form? (Assume ideal gas behavior.) atm

Answer 1

Solution :

Om @ VOL R 9% Ë 11:41 AM 22_PSA_Week_6... @ At : © 6.879 - 1212/27+226.4 > 124.75 Peta 104.2 XA=0.28 XB=0.72 YA PATXA/P = 0.318 Yo = 0.682 a. h = 50% = W0P=0.50P2,0 (90°C) Table B.3. 0.50 x 525.76 mm Hg = 0.346 mol H,O/mol 760.0 mm Hg Dew Point: Yu_OP=P*(T) = 0.346(760) = 262.9 mm Hg Table 3.1 Degrees of Superheat = 90 - 72.7 = 17.3°C of superheat Ty = 72.7°C 1 m feed gas 10 L 273K mol b. Basis = 33.6 mol m 363K 22.4 L (STP) . PHỤo(25°C) 23.756 Saturation Condition: y =-* = P 760 = 0.0313 mol H2O/mol Dry air balance: 0.654(33.6)= (1-0.0313) , = 22.7 mol Total mol balance: 33.6=22.7+n, n, = 10.9 mol H,O condense/m C. POP=p* (90°C)=P-p (90°C) 525.76 mmHg 19 = 1520 mm Hg = 2.00 atm .0 0.346 3. Assume a T. Use Antoine's Law to find vapor pressure of both benzene and toluene at specific temperature log p = A- 7+ Then sum the partial pressures of the two components. This summation should be equal to

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