A electric model train travels at 34.7 cm/s around a circular track of radius 1.67 m....
A electric model train travels at 34.7 cm/s around a circular track of radius 1.67 m. How many revolutions does it perform per second, i.e, what is the motion\'s frequency?
Find the train\'s period of revolution.
Homework Answers
Distance for complete revolution= perimeter of track
=2*pi*r=2*3.14*1.67=10.493 m
Speed of train=34.7 cm/s=0.347 m/s
Revolution performed per sec=speed/ Distance in one rev =10.493/0.347
=0.033 rev/sec
Period of rev= 1/0.033=30.24 sec
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