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Consider the dissolution of CaF2 in aqueous solution: CaF2 (s) ⇌ Ca(+2) (aq) + 2F(-) (aq)....

Consider the dissolution of CaF2 in aqueous solution: CaF2 (s) ⇌ Ca(+2) (aq) + 2F(-) (aq). If we start with 1M of undissolved CaF2 in a solution that already contains 0.015M of F(-) ions, what is the solubility of CaF2 at 298.15K in terms of molarity? (Hint: Look at the final simulated concentration of Ca(+2).)

A. 3.7E-7 M

B. 2.5E-6 M

C. 1.2E-5 M

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