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ch 15 rev q4 The Condé Nast Traveler Gold List for 2012 provided ratings for the...

ch 15 rev q4

The Condé Nast Traveler Gold List for 2012 provided ratings for the top 20 small cruise ships (Condé Nast Traveler website, March 1, 2012). The data shown below are the scores each ship received based upon the results from Condé Nast Traveler's annual Readers' Choice Survey. Each score represents the percentage of respondents who rated a ship as excellent or very good on several criteria, including Itineraries/Schedule, Shore Excursions, and Food/Dining. An overall score was also reported and used to rank the ships. The highest ranked ship, the Seabourn Odyssey, has an overall score of 94.4, the highest component of which is 97.8 for food/dining.

Click on the datafile logo to reference the data.

datafile.jpg

ansm13h_ch15_25.png

a. Determine the estimated regression equation that can be used to predict the overall score given the scores for Itineraries/Schedule, Shore Excursions, and Food/Dining. Round your answers to three decimal places.

The regression equation is
Overall =   +   Itineraries/Schedule +   Shore Excursions +   Food/Dining

b. Use the F test to determine the overall significance of the relationship. Round your answers to two decimal places.

What is the conclusion at the .05 level of significance?
- Select your answer -The overall model is significant.The overall model is not significant.Item 6

c. Use the t test to determine the significance of each independent variable.

Itineraries/Schedule - Select your answer -This variable is significant.This variable is not significant.Item 7
Shore Excursions - Select your answer -This variable is significant.This variable is not significant.Item 8
Food/Dining - Select your answer -This variable is significant.This variable is not significant.Item 9

What is your conclusion at the .05 level of significance?

Itineraries/Schedule - Select your answer -Greater than the level of significance.Less than the level of significance.Item 10
Shore Excursions - Select your answer -Greater than the level of significance.Less than the level of significance.Item 11
Food/Dining - Select your answer -Greater than the level of significance.Less than the level of significance.Item 12

d. Remove any independent variable that is not significant from the estimated regression equation. What is your recommended estimated regression equation? Round your answers to three decimal places.

Overall =   +   - Select your answer -Itineraries/ScheduleShore ExcursionsFood/DiningItem 15  +   

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Answer #1

Excel > Data > Data Analysis > Regression

Н K 1 Overall Itineraries/ Schedule Shore Excursions Food/ Dining Regression 94.6 94.4 90.9 97.8 Input Ок 96.7 84.2 93 96.7 I

SUMMARY OUTPUT
















Regression Statistics






Multiple R0.865921774






R Square0.749820518






Adjusted R Square0.702911865






Standard Error1.387747298






Observations20















ANOVA








dfSSMSFSignificance F


Regression392.3520189930.7840063315.984695184.51741E-05


Residual1630.813481011.925842563




Total19123.1655















CoefficientsStandard Errort StatP-valueLower 95%Upper 95%Lower 95.0%Upper 95.0%
Intercept35.6183775213.230827532.6920748120.0160300177.57027613963.666478917.57027613963.66647891
Itineraries/ Schedule0.1104538650.1296622130.8518585510.406862775-0.1644177470.385325477-0.1644177470.385325477
Shore Excursions0.2445374230.0433573175.6400497583.68903E-050.1526240180.3364508280.1526240180.336450828
Food/ Dining0.2473567630.0621165873.9821370380.0010715270.115675480.3790380450.115675480.379038045

a)

The regression equation is

Overall = 35.618 +0.111 * Itineraries/Schedule +0.245 * Shore Excursions +0.247 * Food/Dining

b)

Hypothesis :

H0 : β1 = β2 = β3 = 0

Ha : at least one β is not equal to 0

Test :

F = 15.98

P value = 0 < 0.05. Reject H0

There enough evidence to conclude that overall model is significant

c)

Independent variablet StatP-value
alphaSignificant
Itineraries/ Schedule0.8518590.406863>0.05No
Shore Excursions5.640053.69E-05<0.05Yes
Food/ Dining3.9821370.001072<0.05Yes

d)

Remove Itineraries/ Schedule variable and again do the same regression model like above

SUMMARY OUTPUT
















Regression Statistics






Multiple R0.859345037






R Square0.738473893






Adjusted R Square0.707706116






Standard Error1.376504389






Observations20















ANOVA








dfSSMSFSignificance F


Regression290.9545063245.4772531624.001535351.11912E-05


Residual1732.210993681.894764334




Total19123.1655















CoefficientsStandard Errort StatP-valueLower 95%Upper 95%Lower 95.0%Upper 95.0%
Intercept45.177958486.9518476896.4986979725.45765E-0630.5108419359.8450750230.5108419359.84507502
Shore Excursions0.2528924740.0418912376.0368824591.33357E-050.164509690.3412752590.164509690.341275259
Food/ Dining0.2481889290.0616057274.0286665360.000871380.1182122080.3781656510.1182122080.378165651

Overall = 45.178 + 0.253 * Shore Excursions + 0.248 * Food/ Dining


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Answer #2

Here is my answer


a.  Determine the estimated regression equation that can be used to predict the overall score given the scores for Itineraries/Schedule, Shore Excursions, and Food/Dining. Round your answers to three decimal places.

The regression equation is
Overall =   +   Itineraries/Schedule +   Shore Excursions +   Food/Dining

b.  Use the F test to determine the overall significance of the relationship. Round your answers to two decimal places.
 

What is the conclusion at the .05 level of significance?
 

c.  Use the t test to determine the significance of each independent variable.

Itineraries/Schedule 
Shore Excursions 
Food/Dining 

What is your conclusion at the .05 level of significance?

Itineraries/Schedule 
Shore Excursions 
Food/Dining 

d.  Remove any independent variable that is not significant from the estimated regression equation. What is your recommended estimated regression equation? Round your answers to three decimal places.

Overall =   +     +    


answered by: Sadhana Pv
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