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Chopter 10 Example Engineers working at a manufacturing plant realized that 15% of their product needed to be recaledn order
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Answer #1

a) H0: P = 0.15

    H1: P < 0.15

The test statistic z = (\widehat p - P)/sqrt(P(1 - P)/n)

                              = (0.095 - 0.15)/sqrt(0.15 * (1 - 0.15)/88)

                              = -1.44

P-value = P(Z < -1.44)

             = 0.0749

Since the P-value is less than the significance level(0.0749 < 0.10), so we should reject the null hypothesis.

So at 0.10 significance level we can conclude that the changes made by the engineers still be considered a significant improvement.

b) H0: P = 0.29

    H1: P \neq 0.29

The test statistic z = (\widehat p - P)/sqrt(P(1 - P)/n)

                              = (0.32 - 0.29)/sqrt(0.29 * (1 - 0.29)/1109)

                              = 2.20

P-value = 2 * P(Z > 2.20)

              = 2 * (1 - P(Z < 2.20))

              = 2 * (1 - 0.9861)

              = 2 * 0.0139

              = 0.0278

Since the P-value is less than the significance level(0.0278 < 0.05), so we should reject the null hypothesis.

So at 5% significance level there is sufficient evidence to conclude that the percentage of CEOs held MBAs has been changed..

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