A pilot wishes to fly a ground path that is 060 degrees The airspeed of the...

Question

Question

A pilot wishes to fly a ground path that is 060 de

Answer 1

Answer #1

Ground speed = vector addition of the speeds

= sqrt(120^2+40^2+2*120*40* cos 60 degree )

= 144.22 mph

120 sin theta = 40 sin 60 degree

sin theta = 0.866/3

theta = arcsin (0.866/3)

= 16.8 degree with groundpath

Or 76.8 degree with east

Answer 2

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