Constants Part A An airplane pilot wishes to fly due west. A wind of 84.0 km/h...

Question

Question

Answer 1

Answer #1

the planes ground speed

V= $\sqrt{}$ airspeed²-windspeed²= $\sqrt{}$ 400²-84²=391km/h

and the angle , to head in the west direction the the north component of the velocity must match the speed of the wind to the south.

tan $\Theta$ =84/391

$\Theta$ =tan^-1(84/391)=12^o

so answer A) 12^o or 12.1^o or 12.12^o b) 391 km/h or 391.1 km/h

Answer 2

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