Question

I know the output of the program I just want help with 
the logic of figuring out the output a step by step processes of how to get to the output.
thank you this is for my study guide please include step by step processes of how to reach output thank you. 

#include <iostream>
using namespace std;

int funcB(int);

int funcA(int n) {
        if (n <= 1)
                return 1;
        else
                return n + funcB(n - 2);
}
int funcB(int n) {
        if (n <= 3)
                return 1;
        else
                return n * funcA(n - 3);
}
int main() {
        int num = 11;
        cout << funcA(num);
        return 0;
}

Answer 1

Code Snippet

   #include <iostream>
   using namespace std;

   int funcB(int);

   int funcA(int n) {
   if (n <= 1)
   return 1;
   else
   return n + funcB(n - 2);
   }
  
   int funcB(int n) {
   if (n <= 3)
   return 1;
   else
   return n * funcA(n - 3);
   }
  
   int main() {
   int num = 11;
   cout << funcA(num);
   return 0;
   }

Output

   101

Explanation

   The code snippet uses the concepts of multiple recursions.

   First Call - funcA(11)   =>   11 + funcB(9)

   Second Call - funcB(8)   =>   11 + ( 9 * funcA(6) )

   Third Call - funcA(6)   =>   11 + ( 9 * ( 6 + funcB(4) ) )

   Fourth Call - funcB(4)   =>   11 + ( 9 * ( 6 + ( 4 * funcA(1) ) ) )

   Final Call - funcA(1)   =>   11 + ( 9 * ( 6 + ( 4 * 1 ) ) )           [returns 1]

  
   Solving the equation 11 + ( 9 * ( 6 + ( 4 * 1 ) ) )

   We get 101.

QED