Question

Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds) E Click the icon to view the data In this example, H is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: Hd 0 О В. Но: На0 0z Pri :TH O D. Ho: Hd 0 О с. Но: На # о 0< Pr:H Identify the test statistic 0> Pri:H (Round to two decimal places as needed.)
Household   Paper   Plastic
1   9.45   3.02
2   6.33   3.86
3   8.72   9.20
4   13.05   12.31
5   12.43   8.57
6   20.12   18.35
7   11.36   10.25
8   5.86   3.91
9   16.08   14.36
10   6.44   8.40
11   11.42   12.81
12   9.55   9.20
13   6.16   5.88
14   2.41   1.13
15   16.39   9.70
16   6.67   6.09
17   6.05   2.73
18   15.09   9.11
19   12.73   14.83
20   9.19   3.74
21   13.31   19.70
22   6.96   7.60
23   7.72   3.86
24   6.98   2.65
25   2.80   5.92
26   17.65   11.26
27   14.33   6.43
28   3.27   0.63
29   6.38   8.82
30   7.57   5.92

Answer 1

The statistical software output for this problem is:

Paired T hypothesis test: PD = V1 -2 : Mean of the difference between Paper and Plastic Ho: PD = 0 HA: P = 0 Hypothesis test results: Difference Mean Std. Err. DF T-Stat P-value Paper - Plastic 1.741 0.60688584 29 2.8687438 0.0076

Hence,

Hypotheses: Option A is correct.

Test statistic = 2.87

P-value = 0.008

Less; Reject; is