Question

Practice Statistic Final for Spring 201 9 A Name: Do 1, 4, 5, 6,7 Or 2, 3, 5, 6, 7 ONE PROPORTION rowning deaths of children
TWO PROPORTIONS In a random sample of 360 women, 65% favored stricter gun control laws. I a random sample of 220 men, 60% fav
Practice Statistic Final for Spring 2019 A Name: Do 1, 4,5, 6,7 Or 2, 3, 5, 6,7 ONE MEAN 1. The health of employees is measur
TWO MEANS A researcher wishes to determine whether people with high blood pressure can reduce their blood pressure by followi
Practice Statistic Final for Spring 2019 A Name: Do 1,4,5,6,7 Or 2, 3, 5, 6,7 5. Chi-Squared Test of Independence Tests for t
Perform the indicated Goodness of Fit Test. 6. Using the data below and a 0.05 significance level, test the claim that the re
Practice Do 1, 4, 5, 6,7 Or 2, 3, 5, 6,7 ANOVA. . A consumer magazine wants to compare the lifetimes of ballipoint pens of th
Practice Statistic Final for Spring 201 9 A Name: Do 1, 4, 5, 6,7 Or 2, 3, 5, 6, 7 ONE PROPORTION rowning deaths of children attributed to beaches is given as 0.25. wring deaths of children has 30% attributed to beaches. 3. The proportion of dro Test the claim that drowning deaths of children attributed to b. Give a 95% Confidence Interval and the EBP. Hypothesis Ho 5 points. 3 points На: p-value Conclusion 6 points b. Give a 95% confidence interval. Confidence 5 points. Interval 5 points ЕВР Conclusion. 6 points
TWO PROPORTIONS In a random sample of 360 women, 65% favored stricter gun control laws. I a random sample of 220 men, 60% favored stricter gun control laws. Test the claim that the proportion of women favoring stricter gun control is higher than the proportion of men favoring stricter gun control. Hypothesis Ho: 4. 5 points. На: 4 points. value Conclusion 6 points.
Practice Statistic Final for Spring 2019 A Name: Do 1, 4,5, 6,7 Or 2, 3, 5, 6,7 ONE MEAN 1. The health of employees is measured periodically by wei employees has a mean weight of 170 pounds with a standa Test the claim that the 4 ghing them. A random sample of s e mean weigh for all such employees is less than 200 pounds 5 points 3 points Hypothesis Ho: Ha: p-value Conclusion points 6 BM b. Find a 95% Confidence lnter Confidence Interval. and give the val 5 points 5 points EBM Conclusion. 6 points.
TWO MEANS A researcher wishes to determine whether people with high blood pressure can reduce their blood pressure by following a particular diet. Use the sample data below to test the claim that those who followed the diet have a lower mean blood pressure than those who 2. did not followed the diet. Followed the diet: n1-85, 189.1 s 38.7 Did not follow the diet: n2-75, 3-203.7 S2-39.2 Hypothesis Ho: На: 5 points. 4 points. p-value Conclusion 6 points.
Practice Statistic Final for Spring 2019 A Name: Do 1,4,5,6,7 Or 2, 3, 5, 6,7 5. Chi-Squared Test of Independence Tests for the adverse reactions to a new drug yielded the results given in the table. At the 0.05 significance level, test the claim that the treatment is independent of the reaction (headache or no headache experienced) DrugPlacebo Headache No headache 91 73 Ho: Hypothesis a: 5 points. Expected Values 5 points Decision 5 points Conclusion 5 points.
Perform the indicated Goodness of Fit Test. 6. Using the data below and a 0.05 significance level, test the claim that the responses with percentages of 15%, 20%, 25%, 25%, and 15% respectfully occur Response-la- B- C - D E Frequency 12 15 16 18 19 HypothesisHo На: 5 points Expected Values 5 points. Decision 5 points. Conclusion 5 points.
Practice Do 1, 4, 5, 6,7 Or 2, 3, 5, 6,7 ANOVA. . A consumer magazine wants to compare the lifetimes of ballipoint pens of three different types Brand 1 Brand 2 Brand 3 181 260 238 240 257 218 1184 |162 219 218 213 Does the data indicate that there is a difference in the mean lifetime of the three brands. 241 Hypothesis Ho: На: 5 points. Decision 5 points. Conclusion 5 points.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

7) Here we have data:

Brand 1 Brand 2 Brand 3
260 181 238
218 240 257
184 162 241
219 218 213

Here we are using Excel for calculation:

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
Column 1 4 881 220.25 966.9167
Column 2 4 801 200.25 1242.9167
Column 3 4 949 237.25 330.9167
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 2744 2 1372 1.6200 0.2507 4.2565
Within Groups 7622.25 9 846.9167
Total 10366.25 11

Hypothesis:

Ho; μ1 = μ2 = μ3

Ha; At least one mean is difference from others.

Decision :

Fail to reject the null hypothesis

Conclusion:

Here we have not sufficient evidence to reject the null hypothesis F-observed value is less than F-critical value and P-value is grater than Alpha value.

We can say that yes: All the three brand mean life is same.

(Note:- Dear student according to HomeworkLib policy one question at a time please repost another.)

Add a comment
Know the answer?
Add Answer to:
Practice Statistic Final for Spring 201 9 A Name: Do 1, 4, 5, 6,7 Or 2, 3, 5, 6, 7 ONE PROPORTION rowning deaths of children attributed to beaches is given as 0.25. wring deaths of children...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • LJidustlc Final for Spring 2019 B Name: Do 1, 4,5,6,7 Or 2,3, 5,6,7 ONE PROPORTION 3. In a clinical study of an allergy drug, 108 of the 202 subjects reported e significant relief from their symp...

    LJidustlc Final for Spring 2019 B Name: Do 1, 4,5,6,7 Or 2,3, 5,6,7 ONE PROPORTION 3. In a clinical study of an allergy drug, 108 of the 202 subjects reported e significant relief from their symptoms. At 0.05 significance level, test th than half of all those using the drug experienced relief. Hypothesis Ho: На: points p-value Conclusion points b. Give a 95% confidence interval. Confidence Interval ЕВР Conclusion TWO PROPORTIONS A marketing survey involves product recognition in New York...

  • #1-6 Review 4 Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or...

    #1-6 Review 4 Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Provide an appropriate response. 1) homeless persons showed that 63 were veterans. Construct a 90% confidence 1) A survey of interval for the proportion of homeless persons who are veterans. D) (0.161, 0.289) C) (0.167,0 283) B) (0.184, 0.266) A) (0.176, 0.274) 2) 2) Given Ho: p z 80% and Ha p: 80% determine whether the hypothesis test is left-tailed right-tailed,...

  • Hotel_Brand_1_Stay_Length   Hotel_Brand_2_Stay_Length 4   5 2   1 2   1 1   5 2   9 5   5 4   6...

    Hotel_Brand_1_Stay_Length   Hotel_Brand_2_Stay_Length 4   5 2   1 2   1 1   5 2   9 5   5 4   6 3   4 8   6 1   4 2   3 1   5 2   8 1   3 4   3 2   1 2   9 2   4 1   4 4   2 6   5 1   2 2   2 2   3 3   1 10   1 5   2 4   4 7   3 4   8 2   5 7   5 2   8 2   5 7   4 5   4 1   2 5   3 1   3...

  • defects 1 4 1 0 3 4 2 1 3 1 0 5 1 3 3...

    defects 1 4 1 0 3 4 2 1 3 1 0 5 1 3 3 2 1 1 4 1 1 2 3 3 1 2 2 2 2 2 4 3 1 1 3 0 6 1 1 3 2 1 3 3 0 1 0 1 3 5A quality control engineer at a particular lcd screen manufacturer is studying the mean number of defects per screen. Based on historical evidence, the mean number of defects per screen...

  • Job Seeker (k) 1 2 3 4 5 5 6 7 8 9 10 11 12...

    Job Seeker (k) 1 2 3 4 5 5 6 7 8 9 10 11 12 13 14 15 Interviews (Xi) 3 5 114 6 7 6 3 Job Offers (Y) 0 2 1 2 2 4. 3 5 1 4 6 100 7 4 8 1 1 8 4 2 (1) (2 points) Your friend Paul, who took Econ 140A last year, says that you should run a hypothesis test to evaluate Cathy's statement. If the null hypothesis is...

  • 4 5 2 2 0.5 2.5 1 2 3.5 6 1.5 2 1 6.5 7 3...

    4 5 2 2 0.5 2.5 1 2 3.5 6 1.5 2 1 6.5 7 3 3 3 1 1.54 6.5 3 2 4 1 2 2 2.5 4 7 1 5 1 2 3 5 7 1 4 6 1.5 2 2 2 2 2 0.5 2 5 4 2 1 2.5 6 2.5 1 4 4 Use the data set provided in the main page of the experience for this application. 1. Complete the full hypothesis testing procedure...

  • Given are five observations for two variables, r and y. 3 4 5 1 2 7 6 11 14 4 The estimated regression equation is...

    Given are five observations for two variables, r and y. 3 4 5 1 2 7 6 11 14 4 The estimated regression equation is y = 1.2 + 2.4r Compute the mean square error using the following equation (to 3 decimals). a. SSE s2=MSE n- 2 decimals). b. Compute the standard error of the estimate using the following equation (to SSE VMSE Vn-2 SE c. Compute the estimated standard deviation bi using the following equation (to 3 decimals). Sp...

  • Household   Paper   Plastic 1   9.45   3.02 2   6.33   3.86 3   8.72   9.20 4   13.05   12.31 5  ...

    Household   Paper   Plastic 1   9.45   3.02 2   6.33   3.86 3   8.72   9.20 4   13.05   12.31 5   12.43   8.57 6   20.12   18.35 7   11.36   10.25 8   5.86   3.91 9   16.08   14.36 10   6.44   8.40 11   11.42   12.81 12   9.55   9.20 13   6.16   5.88 14   2.41   1.13 15   16.39   9.70 16   6.67   6.09 17   6.05   2.73 18   15.09   9.11 19   12.73   14.83 20   9.19   3.74 21   13.31   19.70 22   6.96   7.60 23   7.72   3.86 24   6.98   2.65 25   2.80   5.92 26   17.65  ...

  • "1",4.69816621546105 "2",4.44756510829146 "3",6.84100846766469 "4",7.01358258791867 "5",3.12935822296976 "6",5.14762683649335 "7",2.54905695207...

    "1",4.69816621546105 "2",4.44756510829146 "3",6.84100846766469 "4",7.01358258791867 "5",3.12935822296976 "6",5.14762683649335 "7",2.54905695207479 "8",4.06103182893184 "9",2.48237691955398 "10", 6.2004516591676 "11", 3.01735627817734 "12", 3.54398983209343 "13",5.02652010457958 "14", 5.94118091122925 "15", 7.01208796523191 "16",1.78016831028813 "17",4.33834121978255 "18", 8.93218857046722 "19", 8.43778411332812 "20",8.85822711493131 "21",4.75013154193281 "22", 9.31373767405901 "23",4.09575976019349 "24",2.74688111585186 "25", 3.8040095716617 26",9.34905953037803 "27", 5.87804953966622 "28",7.30637945593767 "29",7.14701470885807 "30",4.48962722844458 "31", 5.04849646123746 "32", 3.97515036133807 "33", 5.32546715405807 "34",8.17769559423788 "35", 6.42260496868865 "36",7.81161965525343 "37",9.8499408616349 "38",9.93608614628273 "39",8.04555405523207 "40",4.14121187997945 "41",5.19842955121368 "42",6.43976800531653 "43", 5.06797870826443 "44",3.79022295456759 "45",8.64229620362652 "46",10.7203765104341 "47",5.45008418851375 "48",4.96026223624637 "49",3.35515355305645 "50",4.3593298786236 Problem 2: Load in the file "data.csv". Assume that this is a random sample from...

  • STA2221 examples on CI & Testing of Hypothesis Name MULTIPLE CHOICE. Choose the one alternative that...

    STA2221 examples on CI & Testing of Hypothesis Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answer the question Provide an appropriate response. 1) Find the critical value,te for 0.99 and n-10. A) 3.250 B) 3.169 1.833 D) 2.262 2) Find the critical value to forc=0.95 and n=16. A) 2.947 B) 2.602 2120 D) 2.131 3) Find the value of E, the margin of error, for A) 1.69 B) 0.42 0.99, n=16 and s=2.6. C)...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT