Solution :
Given that,
Point estimate = sample mean =
= 35
sample standard deviation = s = 18
sample size = n = 10
Degrees of freedom = df = n - 1 = 10-1 = 9
At 98% confidence level
= 1-0.98% =1-0.98 =0.02
/2
=0.02/ 2= 0.01
t/2,df
= t0.01,9= 2.82
t
/2,df = 2.82
Margin of error = E = t/2,df
* (s /
n)
= 2.82 * (18 /
10)
Margin of error = E = 16.05
The 98% confidence interval estimate of the population mean is,
E
35
16.05
19.0 <
< 51.0
(19.0,51.0)
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