Question

If an apterous female fruit fly with wild type (+) red eyes is crossed with a white eyed male with normal wild type wings, what is the resting F1 generation? Please show on a punnet square.Also what is the punnet dihybrid cross for the F2 generation.

Note: the recessive white eyed allele is X-linked while the apterous (wingless) recessive allele is NOT x-linked.

SO to summarize: male with recessive white eyes and with normal wild type wings and a recessive apterous female with normal wild type red eyes cross to produce F1s...then cross those F1s to produce F2s. The F1 should not have any homozygous recessives, but the F2 should I believe.  

Combining x-linked and non x-linked alleles in a dihybrid cross confuses me. I need help understanding this so I can comprehend what the expected phenotypic and genotypic ratios should be for the lab we completed. I really want to understand this!!! Thank you!

Answer 1

As the alleles for red or white eye is x' linked so they should be represented with X or Y. The symbols taken for this cross is given below:

→ allele foor red eye which is a linked you allele for white eye which is a linked → allele for nocomal wing 1 autosomal altele for apteroces wings GRAR aa x XV AA Red eyed and white eyed and apterous fernale normal wirled male Do a ti progenies yo . YA 1 xRx Aa | XRyAa Red eyed and Red eyed normal noomal wind a wing of IXa Hybridization of ti - x*x*^2 * xyaa Gamefes - XPA tha XA Xoa XA XRa Ya Ya

x*x“AA x' ХАа х*YAA хүAA x xk Aa Xhaa yRYAR XK Yaa х:"AA xx“Аа хүAA хүA4 uR or ххаа phenotypie radio to 9:3:3:1