You will estimate how much slower an ice skater would spin, if a can of soda...
You will estimate how much slower an ice skater would spin, if a can of soda dropped into her hand while she was spinning. You may model her body as a vertical cylinder of radius 20 cm and mass of 50 kg, spinning about a vertical axis. Assume that she's initally spinning 10 times per second, so that initially wi=20 (pi)s-1. Suddenly she is handed the soda can, which is small enough that we can model it as a point-like mass of .33kg, which she holds at a distance of 60 cm from the axis of rotation. (a) find the moment of inertia of the ice skater before the soda can drops in her hand. (b) find the moment of inertia of the point-like soda can relative to the axis about which the ice skater rotates. (c) find the total moment of inertia of the system conisting of the ice skater and the soda can. (d) find her final angular velocity wf, after the soda can falls into her hand and (e) calculate the percentage deviation, compared to her initial angular velocity wi.
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You will estimate how much slower an ice skater would spin, if a
can of soda...
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the...
An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the skater pulls in her arms, her moment of inertia decreases to 50.0 kg•m2. What is the skater’s resulting angular velocity?
A figure skater is spinning on frictionless ice. Treat the figure skater as a sphere with...
A figure skater is spinning on frictionless ice. Treat the figure skater as a sphere with radius R=.4m and mass M=60kg. The skater is holding onto a massless string attached to a weighted ball of m=10kg. The skater is initially spinning at an angular speed w0 of 2pi radians per second (1 rev/s) with a sting radius of r=1m. Moment of inertia for a sphere is I=(2/5)MR^2. 1.) What is the initial total rotational inertia of the skater and ball?...
An ice skater is spinning at a particular rotational velocity when she decides to bring her...
An ice skater is spinning at a particular rotational velocity when she decides to bring her arms inward, thus reducing her moment of inertia. If she reduces her moment of inertia by 20.0%, her rotational velocity will increase by what percent?
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia...
An ice skater is spinning at 2.5 revolutions per second and has a moment of inertia of 0.85 kg m2. Estimate her rotational angular momentum, assuming for simplicity that she can be approximated as a rigid, axially-symmetric body.
If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity...
If an ice skater has a rotational inertia of 100 kg*m^(2)while spinning with an angular velocity of 2 rad/s, what is the ice skaters angular velocity if she changes her rotational inertia to 50 kg*m^(2)?
7. An ice skater can be modeled bv a cylinder of radius R and length L...
7. An ice skater can be modeled bv a cylinder of radius R and length L (trunk and legs together), 2 small thin cylinders. of radius r and length l (arms), and a sphere also of radius R (head). The head has mass mh, the trunk mt, and the arms ma. The ice skater rotates about her central axis. Find the moment of inertia of the ice skater with arms outstretched horizontally and then with arms vertical.
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and...
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
A skater extends her arms horizontally, holding a 5-kg mass in each hand. She is rotating...
A skater extends her arms horizontally, holding a 5-kg mass in each hand. She is rotating about a vertical axis with an angular velocity of one revolution per second. If she drops her hands to her sides, what will the final angular velocity (in rev/s) be if her moment of inertia remains approximately constant at 5 kgxm2, and the distance of the masses from the axis changes from 1 m to 0.1 m? O 3 04 07 06
Calculate the angular momentum, in kg · m2/s, of an ice skater spinning at 6.00 rev/s...
Calculate the angular momentum, in kg · m2/s, of an ice skater
spinning at 6.00 rev/s given his moment of inertia is 0.330 kg ·
m2.
(a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
An ice skater spins, with her arms and one leg outstretched, and achieves an angular velocity...
An ice skater spins, with her arms and one leg outstretched, and achieves an angular velocity of 2 rad/s. when she pulls in her arms, her moment of inertia decreases to 65% its original value. what is her new angular velocity?
7. An ice skater can be modeled bv a cylinder of radius R and length L (trunk and legs together), 2 small thin cylinders. of radius r and length l (arms), and a sphere also of radius R (head). The head has mass mh, the trunk mt, and the arms ma. The ice skater rotates about her central axis. Find the moment of inertia of the ice skater with arms outstretched horizontally and then with arms vertical.
Question 8 (6 points) A 60.0-kg skater is spinning at 0.800 rev/s with her arms and legs extended outward. In this position her moment of inertia with respect to the vertical axis about which she is spinning is 6.00 kg•m?. She pulls her arms and legs in close to her body changing her moment of inertia to 2.00 kg•m². What is her final angular velocity in rad/s? a) 8.71 rad/s b) 15.1 rad/s c) 2.40 rad/s d) 0.800 rad/s e)...
A skater extends her arms horizontally, holding a 5-kg mass in each hand. She is rotating about a vertical axis with an angular velocity of one revolution per second. If she drops her hands to her sides, what will the final angular velocity (in rev/s) be if her moment of inertia remains approximately constant at 5 kgxm2, and the distance of the masses from the axis changes from 1 m to 0.1 m? O 3 04 07 06
Calculate the angular momentum, in kg · m2/s, of an ice skater
spinning at 6.00 rev/s given his moment of inertia is 0.330 kg ·
m2.
(a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
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