Question

please define a formula unit in your explanation. What does 3.3 *10^24 forumla units of silver phosphate mean? I know that a formula unit is the ratio of the ions in an ionic compound but how ido you apply 3.3*10^24?

2. Use the information in the answers you obtained in question number one as necessary to answer the following questions. a. Determine the number of moles in 3.3 x 10-4 formula units of silver phosphate. b. Determine the mass of 1.33 moles of Copper(II) hydroxide. c. How many atoms of chlorine would be in .133 moles of phosphorous pentachloride? d. How many grams would 3.33 x 10 molecules of carbon monoxide have? e. Determine the concentration of a solution that has 111 grams of potassium sulfite dissolved in enough water to make 988 mL of solution. f. How many grams of potassium sulfite would be in 400. mL of a .680 M solution?

Answer 1

2. a) Silver phospheute » Ag Pou is this whole formula unit 3.3x1024 pormula units. no. of moles = 3.361024 so NA = Avagadro No = 6.023x 1023 NA = 3.3x1024 6.023x 1023 5.5 moles / n= Copper (1) Hydroxide ) Cu (OH)2 = 1.33 mol MM = 63.55+2 (16+1) MM = 97.56 gm/mol W cucoH)2 = (1-33 * 97.56) gm IWCulohla = 129.75 gm Ane Phosphorous pentachionicle = Pais 9 0.133 moles moles of ci-atom = 5*.133 = 0.665 mol total no. of cl-atom = 0.665x6.022 X 1023 Noi = 4 x 1023 atoms c) Jane

d) Carbon Mono Oxide = co = 3.3 3 x 1023 MM = 12 + 16 = 28 gm/rol no. of moles of ro = 3.33 x 1023 6.023 x 1023 - nco= 0.547 mol wco - 0.547 x 28) gm => Wco = 15.34 gm e) Potassium sulphite & k₂s = 11igm MM = (2x 39.1 + 32) = 110262 gsind nk2S = 11t nol volume =988 ml 110.26 -0.988 Lit Molarity = K25 / 110.26 volume (lit) 0.988 Molarity = 1.02 M 1 Ane volume = 4oome = 0.4 lit Molinity = 0 680M no of moles = volume & Molarity n = (0.4 x 0.68) mol => 0.272 mol W kas =(0.272 x 111) gm Wkas = 30.2 gm Ane