find the speed and orbit radius for an earth satellite with a perioud of 1 day (86400s)
so for to get speed, its v= sqrt (gm/r)
and to get orbit r its v=2pir/t -> r=t*v/2pi ???
answer is v=3.07 * 10^3 m/s r= 4.23 * 10^7 m
i dont get it., how the hell u get 3.07 for v ?????? wth?
r = [GmT^2/4pi^2]^1/3
putting the value
r = 4.2x10^7 m
V = sqrt(Gm/r)
here G = universal constant = 6.67 x 10^-11 Nm^2/kg^2
m = 5.974 x 10^24 kg
r = 4.23 x 10^7 m
put all value in v = sqrt(Gm/r)
v = sqrt(9419995.272 )
v = 3069.20 = 3.07x 10^3 m/s
find the speed and orbit radius for an earth satellite with a perioud of 1 day...
Find the speed of a satellite in a circular orbit around the Earth with a radius 2.77 times the mean radius of the Earth. (Radius of Earth -6.37x103 km, mass of Earth 5.98x1024 kg, G - 6.67x10 11 Nm2/kg2.)
Q12-2 Gravitation 1. Find the speed of a satellite in a circular orbit around the Earth with a radius 2.71 times the mean radius of the Earth. (Radius of Earth = 6.37 x 10 km, mass of Earth = 5.98 x 1024 kg, -6.67 x 10" Nm /kg.) (in m/s) 2 V- 5.67 XII VA
1) A small satellite orbits the Earth in an orbit of speed 3100 m/s and radius 3.6 × 107 m. The gravitational attraction keeping it in orbit has strength 12 N. What is the mass of the satellite?
A satellite in a circular orbit around the earth with a radius 1.015 times the mean radius of the earth is hit by an incoming meteorite. A large fragment (m = 89.0 kg) is ejected in the backwards direction so that it is stationary with respect to the earth and falls directly to the ground. Its speed just before it hits the ground is 359.0 m/s. Find the total work done by gravity on the satellite fragment. RE 6.37·103 km;...
A satellite is launched to orbit the Earth at an altitude of 3.45 x 10^7 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97 x 10^24 kg and its radius 6.38 x 10^6 m. What is the orbital period of this GPS satellite? With what speed does it orbit the Earth?
A satellite is launched to orbit the Earth at an altitude of 2.85 times 10^7 m for use in the Global Positioning System (GPS). Take the mass of the Earth to be 5.97 times 10^24 kg and its radius 6.38 times 10^6 m. What is the orbital period of this GPS satellite? With what speed does it orbit the Earth? What distance does the satellite cover in one revolution? m/s
A satellite is in a circular orbit around the Earth at an altitude of 2.52 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law: T2 =(4π^2/GMs)r^3 so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.) _______________h (b) Find the speed of the satellite. _________km/s (c) Find the acceleration of the satellite....
4. A 1000-kg satellite in circular orbit around the Earth is moving at a speed of 7 x 10 m/s. How much work must be done to "raise" the satellite to a higher circular orbit doubling its height above the surface of the Earth?
6) The period of a satellite in orbit around the Earth is approximately P = 90 R”2 minutes, with R being the radius of the orbit in Earth radii (a unit of about 4000 miles). Suppose that a satellite in an orbit with R = 1.1 Earth radii is observed by radar tracking to have its period changing at a rate di -0.1 day . At what rate a is the radius of its orbit changing in miles per day?...
A satellite is in orbit about Earth. Its orbital radius is 5.56×107 m. The mass of the satellite is 8541 kg and the mass of Earth is 5.974×1024 kg. Determine the orbital speed of the satellite in mi/s. 1 mi/s = 1609 m/s.