SSbetween=SStotal-SSwithin = 2113.833-1483=630.833
MSbetween =SSbetween/df
df=SSbetween/MSbetween = 630.833/210.2778 =2.999999
so, Df~3
so, no of treatments = 3+1 = 4
D | Question 26 Refer to the following partial ANOVA results from Excel (some information is...
Refer to the following partial one-factor ANOVA results from excel (some information is missing. And you need to work it out in the questions below.) Now, the F statistic is equal to: Source of Variation Sum of Squares Degrees of Freedom Mean Square F statistic Between Groups 210.2788 Within Groups 1483 74.15 Total 2113.833 4.79 3.56 1.15 2.84 Referring to the table in question 1. The sum of squares for between groups variation is: 129.99 630.83 1233.4 We cannot tell...
Refer to the following partial ANOVA results from EXCEL. source of variation ss df MS F-sta among-group 172.740 43.185 within-group 508.972 total total # of observation: 58 e. the critical value , F x at x=0.05 (3 decimals) f. at x= 0.05 your conclusion for testing the null hypothesis is that all the groups have the same mean is:
CH13 Q2 a. Given the following information obtained from four normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "F' to 3 decimal places.) ANOVA Source of Variation Between Groups Within Groups Total df MS p-value 0.018 0.00 0
a. Given the following information obtained from three normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "P' to 3 decimal places.) SSTR = 220.7; SSE = 2,252.2; c = 3; ni = n2 = n3 = 8 ANOVA Source of Variation SS df MS F p-value Between Groups 0.375 Within Groups 0.00 0 Total b. At the 1% significance level,...
Consider the following ANOVA summary table: ANOVA Summary Table SS df MS Source F 9 7.3 Group (Between) Error (Within) Total 2400 30 The researcher was comparing 9 groups and found there were no significant differences between the groups. o The researcher was comparing 8 groups and found there were significant differences between the groups. O None of the choices give a correct description of study design and results. o The researcher was comparing 9 groups and found there were...
a. Given the following information obtained from four normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "f' to 3 decimal places.) SST = 78.95; SSTR = 18. 16; C = 4; n1 = n2 = n3 = n4 = 15 df ANOVA Source of Variation Between Groups Within Groups Total p-value 0.002 b. At the 10% significance level, what is...
Interpret the results of the following ANOVA summary table. Make sure to include the decision about the null hypothesis and a sentence explaining the results. Source SS df MS F Between-Groups 60.72 3 20.24 3.88 Within-Groups 213.61 41 5.21 Total 274.33 44
Question 12 15 pts The following table summarizes the results of a two-factor ANOVA evaluating an independent-measures experiment with two levels of factor A, three levels of factor B, and n = 5 subjects in each separate sample. Fill in all missing values in the table. (Hint: Start with the df column.) Source SS df MS 60 Between Treatments Factor A FA = 5 Factor B _ — FB = AXB 30 FAXB = N Within Treatments Total HTML Editor...
4. ANOVA calculations and rejection of the null hypothesis The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation dlass, a high school preparation dlass, and no preparation dass. Use the information from the table to answer the remaining questions. Number of Observations Treatment Sample Mean Sum of Squares (SS) Private prep dlass 40 610 97,500.00 High school prep class 40 600 101,400.00 No prep class 40 590...
QUESTION 20 How would we report the following results of a t-test? One-Sample Test Test Value = 7 95% Confidence interval of the Mean Difference Sig (2-tailed) Difference Lower Upper Digitspan 2 364 68 021 542029 8 457 9.9949 t(68) = 2.364, p = .021 t(67) = 2.364, p = .021 t(68) = 5.42, p = .021 t(68) = .021, p = 2.364 QUESTION 21 Fill in the missing numbers in the ANOVA table below: ANOVA Source of Variation S...