Calculate the time necessary for1 liter of water, initially at 20°C and containedin a cylindrical pot of diameterdP=25cm,to boil on a stove that delivers 10kW/m2.
Energy needed to boil the water
Q = m C deltaT = (1kg)(4186 J / kg deg C) (100 - 20)
Q = 3.35 x 10^5 J
Power = (10 kW / m^2) ( pi D^2 / 4)
= (10 x 10^3 W / m^2) (pi (0.25/2)^2)
= 490.9 W
Power x time = energy
t = (3.35 x 10^5) / 490.9
t = 683.5 sec = 11.4 min
Calculate the time necessary for1 liter of water, initially at 20°C and containedin a cylindrical pot...
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