A mass m with speed u approaches a stationary mass M. The masses collide and assuming 1D motion what are the final velocities v and V of masses m and M respectively in terms of the masses and u.
A mass m with speed u approaches a stationary mass M. The masses collide and assuming...
Part A Masses m and 3m approach at the same speed and collide head-on. Find the final speed of mass 3m, while mass m rebounds at speed 2u Express your answer in terms of the variables m and u. EVO AEP O ? The correct answer does not depend on No credit lost. Try again Submit Previous Answers Request Answer
Problem 4 10 marks Two solid spheres of total masses m, and m,2 respectively collide such that at the instant of impact the x axis passes through the centers C1 and C2 of the spheres. The collision is perfectly elastic (that is, (vi - v2) =-(v^-v2) î). Find their velocities after impact (vi and v) in terms of their velocities before impact (vi and v2 or vi, V2,1 and 02). j C2 2/ 01
Two balls, of masses m and 2m, travelling in a vacuum with initial velocities 2v and v respectively, collide with each other head-on, as shown. m 2v v 2m After the collision, the ball of mass m rebounds to the left with velocity v. What is the loss of kinetic energy in the collision? A 3/4 mv^2 B 3/2 mv^2 C 9/4 mv^2 D 9/2mv^2 10 Two balls, of masses m and 2m, travelling in a vacuum with initial velocities...
A puck of mass 0.70 kg approaches a second, identical puck that is stationary on frictionless ice. The initial speed of the moving puck is 5.0 m/s. After the collision, one puck leaves with a speed vi at 30° to the original line of motion. The second puck leaves with speed v2 at 60°. (a) Calculate V1 and v2. Vi = 866025 x Vy = 250011 x m/s m/s (b) Was the collision elastic? Yes No eBook
по прос- асар тосс пти 61. Mass m, moving at speed 2v, approaches mass 4m, movine speed v. The two collide elastically head-on. Find expressions for their subsequent speeds. Olo on doo
Masses my and m2, traveling with velocities +v; and -u respectively have a head on collision. After the collision, mass mi is at rest while mass me moves with velocity +us (same direction as +v). a) Draw a sketch of both situations, labeling the information you've been given (3 points) b) Without assuming anything about Energy, prove that m2 = m (7 points) c) Suppose vy is such that the collision is completely INELASTIC. What is m2 in terms of...
Mass m = 0.1 kg moves to the right with speed v=0.64 m/s and collides with an equal mass initially at rest. After this inelastic collision the system retains a fraction = 0.82 of its original kinetic energy. What is the speed VR (in m/s) of the mass which was originally at rest before the collision? Hints: All motion is in 1D. Ignore friction between the masses and the horizontal surface. You will probably need to use the quadratic formula...
Mass m = 0.1 kg moves to the right with speed v = 0.44 m/s and collides with an equal mass initially at rest. After this inelastic collision the system retains a fraction = 0.61 of its original kinetic energy. What is the speed VR (in m/s) of the mass which was originally at rest before the collision? Hints: All motion is in 1D. Ignore friction between the masses and the horizontal surface. You will probably need to use the...
Mass m = 0.1 kg moves to the right with speed v = 0.44 m/s and collides with an equal mass initially at rest. After this inelastic collision the system retains a fraction = 0.61 of its original kinetic energy. What is the speed VR (in m/s) of the mass which was originally at rest before the collision? Hints: All motion is in 1D. Ignore friction between the masses and the horizontal surface. You will probably need to use the...
Mass m = 0.1 kg moves to the right with speed v = 0.63 m/s and collides with an equal mass initially at rest. After this inelastic collision the system retains a fraction = 0.87 of its original kinetic energy. What is the speed VR (in m/s) of the mass which was originally at rest before the collision? Hints: All motion is in 1D. Ignore friction between the masses and the horizontal surface. You will probably need to use the...