A bullet traveling at 250 m/s hits a wooden block initially at
rest and is embedded in it. The speed of the block just after the
bullet is embedded is 7 m/s. What is the ratio of the mass of the
block to the mass of the bullet?
This question was answered before, here is the explanation: -How
did this person get to the step, 243/7 * m_b = m?
mb= mass of bullet
m= mass of block
v1= initial velocity of bullet
v= velocity of bullet+ block
By conservation of momentum
mb v1= (mb+m) v
mb* 250= (mb+m)*7
(250/7)mb= mb+m
250/7= (mb+m)/mb = (mb/mb)+(m/mb)= 1+( m/mb)
250/7=1 +(m/mb)
m/ mb =( 250/7)-1= (250-7)/7= 243/7= 34.71
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