Question

1) To make a hologram using an Argon laser (λ-: 0.488 μm), the maximum angle between objective and reference beams is max resolution (or spatial frequency) of the holographic recording film (fo-lines per mm)? 40. What is the requirement on the minimum 2) When the hologram is reconstructed using a HeNe laser (λ 0.633 μm). Assume that Zo- 10cm, Zr-2Zo, zpー00, please compute virtual and real image locations (+2), the transversal and axial magnification (Mt and Ma).

Answer 1

Given that lambda = 0.488 mu m theta_max = 40 degree So, we have to consider the diagram. In this we have to show the hologram. So, here 2 alpha = theta_max 2 alha = 40 alpha = 40/2 alpha = 20 So, Fringe spacing 'f_0' is given by f_0 = lambda/2 times sin lambda cos(n) \r\n So, the Minimum resolution of tilt angle. So, that The resolution is given by R_0 = 1/f = 2 sin(alpha) cos(r)/lambda = 2 sin(alpha) cos(0)/lambda [Therefore here cos(0) = 1] = 2 sin(alpha)/lambda = 2 sin(20 degree)/0.488 times 10^-6 = 1401721.89 = 1.40 times 10^6 lines/mm So, finally R = 1.4 M lines/MM