Compute the time complexity for each of the following two program fragments with respect to N. Show your steps in reaching your answer.
1) for(i=1; i < N; i = i*2) {
for(j=0;j
// Operations with constant time…
} }
2) for(i = 0; i < sqrt(N); i++){
for(j=1; j < i+8; j++){
for(k=0;k
// Operations with constant time…
} } }
1)
it will be nlogn.
for the first loop it is multiplication by i and second loop in j is dependent on i and will run for n times as well so it will be nlogn.
2)
it should be roughly n2 as the second first and second loop are dependent and will run together for roughly n times and the k for will run for n more times so n2
Compute the time complexity for each of the following two program fragments with respect to N....
1- Find the time complexity of the following program, where n is given as input: i = n; while (i > 1) { j = i; while (j < n) { k = 0; while (k < n) { k += 2; } j *= 2; } i /= 2; } Express your answer using theta notation, and explain the amount of time it takes for each loop to finish.
For each of the following six program fragments: a. Give an analysis of the running time (Big-Oh will do). b. Implement the code in the language of your choice, and give the running time for several values of N. Pseudo Code Implementation Analysis of runtime time (Big-Oh) (1) sum = 0; for(i = 0; i < n; ++i) ++sum; (2) sum = 0; for(i = 0; i < n; ++i) for(j = 0; j<n; ++i) ++sum; (3) sum = 0;...
Using C++ please explain
What is the Big-O time complexity of the following code: for (int i=0; i<N; i+=2) { ... constant time operations... Select one: o a. O(n^2) O b. O(log n) c. O(n) O d. 0(1) What is the Big-O time complexity of the following code: for(int i=1; i<N; i*=2) { ... constant time operations... Select one: O O a. O(n^2) b. 0(1) c. O(n) d. O(log n) O What is the Big-O time complexity of the following...
Show the output produced by each of the following program fragments. Assume that I, j, k are int variables i = 7; j = 2; printf(“%d %d ”, i / j, i % j); i = 4; j = 3; printf(“%d”, (i + 10 ) % j); i = 7; j = 8; k = 9; printf("%d”, (i + 10) % k / j); Show the output produced by each of the following program fragments. Assume that I, j, k...
Question 3: Given the following two
code fragments [2 Marks]
(i)Find T(n), the time complexity (as
operations count) in the worst case?
(ii)Express the growth rate of the
function in asymptotic notation in the closest bound possible.
(iii)Prove that T(n) is Big O (g(n)) by
the definition of Big O
(iv)Prove that T(n) is (g(n)) by using
limits
Question 1 (25 pts)
Find the running time complexity for the following code
fragments. Express your answers using either the Big-O or Big-Θ
notations, and the tightest bound possible. Justify your
answers.
for(int count O , i -0; i < n* n; i++) for(int i0 ; j <i; j++) count++
for(int count O , i -0; i
discrete math
(1) (15 pts) Time Complexity Analysis 1) (5 pts) What is the time complexity of the following code segment? Explain your answer; otherwise, you can't get full mark from this question. for(int i=1; i<n; i*=2) { sum-0; sum++; Answer: 2) (5 pts) What is the time complexity of the following code segment? Explain your answer; otherwise, you can't get full mark from this question. for(int j=0; j<n; j++){ for (int k=0; k<n; k++) { for (int =0; i<n;...
Show your work Count the number of operations and the big-O time complexity in the worst-case and best-case for the following code int small for ( i n t i = 0 ; i < n ; i ++) { i f ( a [ i ] < a [ 0 ] ) { small = a [ i ] ; } } Show Work Calculate the Big-O time complexity for the following code and explain your answer by showing...
find complexity Problem 1 Find out the computational complexity (Big-Oh notation) of the code snippet: Code 1: for (int i = n; i > 0; i /= 2) { for (int j = 1; j < n; j *= 2) { for (int k = 0; k < n; k += 2) { // constant number of operations here } } } Code 2: Hint: Lecture Note 5, Page 7-8 void f(int n) { if (n...
(10') 6. For each of the following code blocks, write the best (tightest) big-o time complexity i) for (int i = 0; ǐ < n/2; i++) for (int j -0: ni j++) count++ i) for (int í = 0; i < n; i++) for (int ni j0 - for (int k j k ni kt+) count++ İİİ) for (int í ー 0; i < n; i++) for(int j = n; j > 0; j--) for (int k = 0; k...