Question

Use the tables on the next page and your initials to generate a ‘cell diagram’ where the first reaction (first initial) is the anode and the second reaction (second initial) is the cathode and determine whether the reaction is spontaneous. For gasses, assume an inert Platinum electrode.

First Initial: K . Last Initial: D

  

Rxn K -->    anode (off table, as a reduction) Zn +2(aq) + 2 e- -----> Zn(s)

Rxn S -->    cathode (off table)       PtCl4 2-(aq) + 2e- -----> Pt(s) + 4Cl-(aq)

a) balanced chemical reaction

b) standard cell potential

c) Is the reaction spontaneous or not?

d) What is the value of the equilibrium constant for your reaction

Show all work please!!!

FIRST INITIAL LAST INITIAL Half-Reaction EwHalf-Reaction E (V) 0.80 0.80 0.77 0.76 0.70 0.56 Aglo) eIag 0.40 MnO, (ag)e MnoCag) Fe.(ag) + 2e + Fe(s) -0456) +2e2(a) -0.50 2H00) +44OH (ag) -Q76 BiO+(ag) + 2 H+(aq) + 3 e--Bi() + H20(/) 0.52 0.40 a(a) 2eZn(s) 2H2O(/) + 2 e-? H2(g) + 2 OH-(aq) 0.32 0.22 Ap-(ag) + 3e-?AIG) 1.66 S0 (ap)+4 H (ag)+2eH,so,(ag)+H 223u(a)Cu (ag 0.16 0.15 0.14 237 Sn(ag) +2e Sm(a) Lat (ag) +3 eLalo) -2.38 SO)+2H(ag)+2eHSg) Half-Reaction E (Half-Reaction 2.87 PbO2(s) + 4H(ag) + 2e-_? PY(aq) + 2H,0? FAg) + 2e-?2F (ag) 11.46 1.98 CrO(ay+14H)e_ 1.82 1.78 1.69 2Cr (a) 7HoU) Ox(g) + 4 H+(ap) + 4e--+2 H20(/) MnO2(s) + 4H(ag) + 2 e--M?(ag) + 2 HJX/) | io,-(ag) + 6H+(aq) + 5 e 12(ag) + 3 H2O(/) | 1.33 1.23 1.21 1.20 P00 4111050()2 4 1.68 AuCl (u) +3Au) +4 C (ag) 1.00 1.51 HNO2(ag) + H+(ag) + e-_? NO(g) + 2H20(1) ag) +4 H,00) Au(a)3cAus) BrO (ag) 12H(ag)+10 0.98 0.96 0.95 0.92 1.50 NO lag)+4Ha)3eNOG) +2 H) CIO,(g) + e-? ClO2-(aq) 2 Hgray) + 2 e-? 2 Hg22+(ay) 1.48

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Answer #1

Cl 七 Add 良+ 七 b) Cottthe VM

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