-The triprotic acid H3A has ionization constants of Ka1 = 4.9× 10–2, Ka2 = 6.0× 10–6, and Ka3 = 2.0× 10–13. Calculate the following values for a 0.0700 M solution of NaH2A
(H+)=?
(H2A-)/(H3A)=?
-Calculate the following values for a 0.0700 M solution of Na2HA.
(H+)=?
(HA2-)/(H2A-)=?
-The triprotic acid H3A has ionization constants of Ka1 = 4.9× 10–2, Ka2 = 6.0× 10–6,...
The triprotic acid H3A has ionization constants of Ka1=5.37×10−3 , Ka2=4.31×10−6 , and Ka3=1.04×10−11 . Calculate the H+ concentration and the ratio [H2A−]/[H3A] for a 0.0170 M solution of NaH2A . [H+]= [H2A−]/[H3A]= Calculate the H+ concentration and the ratio [HA2−]/[H2A−] for a 0.0170 M solution of Na2HA . [ H + ]= [HA2−]/[H2A−]=
A triprotic acid, H3A has the following Kas: Ka1 = 4.22 x 10-4 , Ka2 = 7.51 x 10-8 and Ka3 = 7.51 x 10-15. What is the Kb of H2A-? QUESTION 5 1 points Save Answer A triprotic acid, H3A has the following Kas: Ka1 = 4.22 x 10-4, Ka2 = 7.51 x 10-8 and Ka3 = 7.51 x 10-15. What is the Kb of H2A?
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A. [H+]=[H+]= MM [H2A−][H3A]=[H2A−][H3A]= Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA. [H+]=[H+]= MM [HA2−][H2A−]=[HA2−][H2A−]=
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A. [H+]=[H+]= MM [H2A−][H3A]=[H2A−][H3A]= Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA. [H+]=[H+]= MM [HA2−][H2A−]=[HA2−][H2A−]=
Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka Calculate the Ht concentration and the ratiofor a 0.0470 M solution of NaH,A. 9.77 x 10-11 H2A [H3 A] H,A H, A] Calculate the H+ concentration and the ratio for a 0.0470 M solution of Na, HA H2A-] [HA2-] IH2AI Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka...
Consider a triprotic acid, H3A, with the following Ka’s: Ka1 = 2.4 x 10-3, Ka2 = 3.5 x 10-7, Ka3 = 1.6 x 10-11. What is the Kb3 value?
The triprotic acid H, A has ionization constants of Kal = 5.82 x 10-2, K:2 = 5.15 x 10-7, and K3 = 4.14 x 10-13. Calculate the Ht concentration and the ratio- [HA] for a 0.0460 M solution of NaH, A. [H2A] [H+] = [HA] [HA] Calculate the H+ concentration and the ratio ha for a 0.0460 M solution of Na, HA. "° [HA] [HP] = [HA2-) [H,A-]
Given a diprotic acid, H2A, with two ionization constants of Ka1 = 3.5× 10–4 and Ka2 = 5.7× 10–12, calculate the pH for a 0.113 M solution of NaHA. PH=
For the diprotic weak acid H2A, Ka1 = 2.0×10-6 and Ka2 = 7.7 × 10-9. What is the pH of a 0.0700 M solution of H_2A? What are the equilibrium concentrations of H2A and A2- in this solution?
arsenic acid (H3AsO4) is a triprotic acid with a Ka1=5E-3 Ka2=8E-8 and Ka3=6E-10. calculate [H+], [OH-], [H3AsO4], [H2AsO4-][HAsO4 2-], and [AsO43-] in a 0.20 M arsenic acid solution.