The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11.
Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A.
[H+]=[H+]=
MM
[H2A−][H3A]=[H2A−][H3A]=
Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA.
[H+]=[H+]=
MM
[HA2−][H2A−]=[HA2−][H2A−]=
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A. [H+]=[H+]= MM [H2A−][H3A]=[H2A−][H3A]= Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA. [H+]=[H+]= MM [HA2−][H2A−]=[HA2−][H2A−]=
The triprotic acid H3A has ionization constants of Ka1=5.37×10−3 , Ka2=4.31×10−6 , and Ka3=1.04×10−11 . Calculate the H+ concentration and the ratio [H2A−]/[H3A] for a 0.0170 M solution of NaH2A . [H+]= [H2A−]/[H3A]= Calculate the H+ concentration and the ratio [HA2−]/[H2A−] for a 0.0170 M solution of Na2HA . [ H + ]= [HA2−]/[H2A−]=
Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka Calculate the Ht concentration and the ratiofor a 0.0470 M solution of NaH,A. 9.77 x 10-11 H2A [H3 A] H,A H, A] Calculate the H+ concentration and the ratio for a 0.0470 M solution of Na, HA H2A-] [HA2-] IH2AI
Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka...
-The triprotic acid H3A has ionization constants of Ka1 = 4.9× 10–2, Ka2 = 6.0× 10–6, and Ka3 = 2.0× 10–13. Calculate the following values for a 0.0700 M solution of NaH2A (H+)=? (H2A-)/(H3A)=? -Calculate the following values for a 0.0700 M solution of Na2HA. (H+)=? (HA2-)/(H2A-)=?
The triprotic acid H, A has ionization constants of Kal = 5.82 x 10-2, K:2 = 5.15 x 10-7, and K3 = 4.14 x 10-13. Calculate the Ht concentration and the ratio- [HA] for a 0.0460 M solution of NaH, A. [H2A] [H+] = [HA] [HA] Calculate the H+ concentration and the ratio ha for a 0.0460 M solution of Na, HA. "° [HA] [HP] = [HA2-) [H,A-]
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A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−12. Calculate the pH and molar concentrations of H2A,H2A, HA−,HA−, and A2−A2− at equilibrium for each of the solutions. A 0.176 M0.176 M solution of H2A.H2A. pH = [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of NaHA.NaHA. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of Na2A.Na2A. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= M
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17. What is the dominant form of aspartic acid (a triprotic acid represented as H3A) at a pH of 2.5 in a water sample (pKal = 1.990, p 22 = 3.900, PK23 = 10.002)? a. H3A and H2A are equal c. H2A b. Н3А d. HA2- 18. What would you expect the pH level in a 25.0 mL sample of 0.22 M hydrazoic acid given its Ka = 2.6 x 10-S? a) 2.62 b) 5.42 c) 7.00 d) 8.97 €)...