The triprotic acid H, A has ionization constants of Kal = 5.82 x 10-2, K:2 =...
Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka Calculate the Ht concentration and the ratiofor a 0.0470 M solution of NaH,A. 9.77 x 10-11 H2A [H3 A] H,A H, A] Calculate the H+ concentration and the ratio for a 0.0470 M solution of Na, HA H2A-] [HA2-] IH2AI Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka...
The triprotic acid H3A has ionization constants of Ka1=5.37×10−3 , Ka2=4.31×10−6 , and Ka3=1.04×10−11 . Calculate the H+ concentration and the ratio [H2A−]/[H3A] for a 0.0170 M solution of NaH2A . [H+]= [H2A−]/[H3A]= Calculate the H+ concentration and the ratio [HA2−]/[H2A−] for a 0.0170 M solution of Na2HA . [ H + ]= [HA2−]/[H2A−]=
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A. [H+]=[H+]= MM [H2A−][H3A]=[H2A−][H3A]= Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA. [H+]=[H+]= MM [HA2−][H2A−]=[HA2−][H2A−]=
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A. [H+]=[H+]= MM [H2A−][H3A]=[H2A−][H3A]= Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA. [H+]=[H+]= MM [HA2−][H2A−]=[HA2−][H2A−]=
-The triprotic acid H3A has ionization constants of Ka1 = 4.9× 10–2, Ka2 = 6.0× 10–6, and Ka3 = 2.0× 10–13. Calculate the following values for a 0.0700 M solution of NaH2A (H+)=? (H2A-)/(H3A)=? -Calculate the following values for a 0.0700 M solution of Na2HA. (H+)=? (HA2-)/(H2A-)=?
A diprotic acid, H2A, has acid dissociation constants of Ka1=1.01×10−4 and Ka2=4.08×10−12. Calculate the pH and molar concentrations of H2A, HA−, and A2−at equilibrium for each of the solutions. A diprotic acid, H, A, has acid dissociation constants of Kal = 1.01 x 104 and K22 = 4.08 x 10-12. Calculate the pH and molar concentrations of H, A, HA, and A? at equilibrium for each of the solutions. A 0.176 M solution of H, A. pH= pH = 1...
A diprotic acid, H2A, has acid dissociation constants of Kai = 3.52 x 10-4 and Ka2 = 2.03 × 10-11 . Calculate the pH and molar concentrations of H2A, HA, and A2- at equilibrium for each of the solutions. A 0.206 M solution of H,A. pH = H2A] HA1 A 0.206 M solution of NaHA pH- [H2A] = [HA-] = A 0.206 M solution of Na,A. pH- [H2A] EA T [A21
Phosphoric acid is a triprotic acid (Kal = 6.9 x 10-, K2 = 6.2 x 10 %, and Kj] = 4.8 x 10-1). (aq), which pK, value should be used in the To find the pH of a buffer composed of H,PO] (aq) and HPO Henderson-Hasselbalch equation? OPK 1 = 2.16 OPK 2 = 7.21 Opka = 12.32 Calculate the pH of a buffer solution obtained by dissolving 11.0 g of KH, PO (s) and 21.0 g of Na, HPO...
For the diprotic weak acid H2A, Kal = 3.2 x 10- and K2 = 6.7 x 10 What is the pH of a 0.0450 M solution of H,A? pH = What are the equilibrium concentrations of H, A and A in this solution? [HA] = A-1 = M
Phosphoric acid is a triprotic acid with the pk, values Kal = 2.148, p 2 = 7.198, and pka3 = 12.375. You wish to prepare 1.000 L of a 0.0200 M phosphate buffer at pH 7.440. To do this, you choose to mix the two salt forms involved in the second ionization, NaH, PO, and Na,HPO4, in a 1.000 L volumetric flask and add water to the mark. What mass of each salt will you add to the mixture? mass...