The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

Question

Question

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11.

Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A.

[H+]=[H+]=

MM

[H2A−][H3A]=[H2A−][H3A]=

Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA.

[H+]=[H+]=

MM

[HA2−][H2A−]=[HA2−][H2A−]=

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

a Given data, Haiz 3:38X163 ;Waltz)=0.064 Kaz=71 278158 Kaz=4.1981 [ht] (kai Kar (nlahzaltkai ko Kait (Natha 13:38103) (2.278 ht. Jкар tag (Nath)+ка, Кю ka2+ (NaOHA) 6.25Х168 )(+x d!)+ 22х189 1227x68) +о. О6ҷо 3. 031 1018 + 7 2+x 1022 О,069 | 303x 201

Add a comment

Answer 2

Similar Homework Help Questions

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration and the ratio [H2A−][H3A][H2A−][H3A] for a 0.06400.0640 M solution of NaH2ANaH2A. [H+]=[H+]= MM [H2A−][H3A]=[H2A−][H3A]= Calculate the H+H+ concentration and the ratio [HA2−][H2A−][HA2−][H2A−] for a 0.06400.0640 M solution of Na2HANa2HA. [H+]=[H+]= MM [HA2−][H2A−]=[HA2−][H2A−]=
The triprotic acid H3A has ionization constants of Ka1=5.37×10−3 , Ka2=4.31×10−6 , and Ka3=1.04×10−11 . Calculate...

The triprotic acid H3A has ionization constants of Ka1=5.37×10−3 , Ka2=4.31×10−6 , and Ka3=1.04×10−11 . Calculate the H+ concentration and the ratio [H2A−]/[H3A] for a 0.0170 M solution of NaH2A . [H+]= [H2A−]/[H3A]= Calculate the H+ concentration and the ratio [HA2−]/[H2A−] for a 0.0170 M solution of Na2HA . [ H + ]= [HA2−]/[H2A−]=
Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and K...

Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka Calculate the Ht concentration and the ratiofor a 0.0470 M solution of NaH,A. 9.77 x 10-11 H2A [H3 A] H,A H, A] Calculate the H+ concentration and the ratio for a 0.0470 M solution of Na, HA H2A-] [HA2-] IH2AI Question 10 of 10 The triprotic acid H, A has ionization constants of Ka141 0- 6.38 x 10-6, and Ka...

-The triprotic acid H3A has ionization constants of Ka1 = 4.9× 10–2, Ka2 = 6.0× 10–6,...

-The triprotic acid H3A has ionization constants of Ka1 = 4.9× 10–2, Ka2 = 6.0× 10–6, and Ka3 = 2.0× 10–13. Calculate the following values for a 0.0700 M solution of NaH2A (H+)=? (H2A-)/(H3A)=? -Calculate the following values for a 0.0700 M solution of Na2HA. (H+)=? (HA2-)/(H2A-)=?
The triprotic acid H, A has ionization constants of Kal = 5.82 x 10-2, K:2 =...

The triprotic acid H, A has ionization constants of Kal = 5.82 x 10-2, K:2 = 5.15 x 10-7, and K3 = 4.14 x 10-13. Calculate the Ht concentration and the ratio- [HA] for a 0.0460 M solution of NaH, A. [H2A] [H+] = [HA] [HA] Calculate the H+ concentration and the ratio ha for a 0.0460 M solution of Na, HA. "° [HA] [HP] = [HA2-) [H,A-]
Given a diprotic acid, H2A , with two ionization constants of ?a1=2.0×10−4 and ?a2=3.1×10−12 , calculate...

Given a diprotic acid, H2A , with two ionization constants of ?a1=2.0×10−4 and ?a2=3.1×10−12 , calculate the pH for a 0.120 M solution of NaHA.

A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−1...

A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−12. Calculate the pH and molar concentrations of H2A,H2A, HA−,HA−, and A2−A2− at equilibrium for each of the solutions. A 0.176 M0.176 M solution of H2A.H2A. pH = [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of NaHA.NaHA. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of Na2A.Na2A. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= M
Picolinic acid is a diprotic acid with ionization constants ?a1=9.80×10−2 and ?a2=4.10×10−6 . Calculate the pH...

Picolinic acid is a diprotic acid with ionization constants ?a1=9.80×10−2 and ?a2=4.10×10−6 . Calculate the pH of a 0.217 M potassium hydrogen picolinate ( KHP ) solution. PH=
Phosphoric acid is a triprotic acid ( K a1 = 6.9 × 10 − 3 M,...

Phosphoric acid is a triprotic acid ( K a1 = 6.9 × 10 − 3 M, K a2 = 6.2 × 10 − 8 M, and K a3 = 4.8 × 10 − 13 M ) . To find the pH of a buffer composed of H 2 PO − 4 ( aq ) and HPO 2 − 4 ( aq ) , which p K a value would you use in the Henderson–Hasselbalch equation? p K a1 = 2.16...

17. What is the dominant form of aspartic acid (a triprotic acid represented as H3A) at...

17. What is the dominant form of aspartic acid (a triprotic acid represented as H3A) at a pH of 2.5 in a water sample (pKal = 1.990, p 22 = 3.900, PK23 = 10.002)? a. H3A and H2A are equal c. H2A b. Н3А d. HA2- 18. What would you expect the pH level in a 25.0 mL sample of 0.22 M hydrazoic acid given its Ka = 2.6 x 10-S? a) 2.62 b) 5.42 c) 7.00 d) 8.97 €)...

The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

Homework Answers

Add Answer to:
The triprotic acid H3AH3A has ionization constants of ?a1=3.38×10−3Ka1=3.38×10−3, ?a2=7.27×10−8Ka2=7.27×10−8, and ?a3=4.17×10−11Ka3=4.17×10−11. Calculate the H+H+ concentration...

Post as a guest

Earn Coins