ln(K2/k1) = Ea/R[1/T1 - 1/T2]
k1 = 3.6*10^10 , T1 = 204+273.15 = 477.15 k
k2 = 6.0*10^10 , T2 = 323.0+273.15 = 596.15 k
Ea = x kj/mol , R = 8.314*10^-3 j.k-1.mol-1
ln((6*10^10)/(3.6*10^10)) = ((x*10^3)/(8.314))((1/477.15)-(1/596.15)
X = Ea = activation energy = 10 kj/mol
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