You run a regression analysis on a bivariate set of data (n obtain the regression equation...
You run a regression analysis on a bivariate set of data ( n = 41 ). With ¯ x = 41.6 and ¯ y = 31.1 , you obtain the regression equation y = − 2.748 x + 61.522 with a correlation coefficient of r = − 0.011 . You want to predict what value (on average) for the response variable will be obtained from a value of 10 as the explanatory variable. What is the predicted response value? You...
You run a regression analysis on a bivariate set of data (n = 53). With i = 46.8 and y = 46.4, you obtain the regression equation y=2.435x + 16.465 with a correlation coefficient of r = 0.413. You want to predict what value (on average) for the response variable will be obtained from a value of 150 as the explanatory variable. What is the predicted response value? (Report answer accurate to one decimal place.) License Points possible: 1 liited...
You run a regression analysis on a bivariate set of data (n = 50). With 7 = 40.2 and y = 41.8, you obtain the regression equation y = -2.644x - 46.854 with a correlation coefficient of r = -0.214. You want to predict what value (on average) for the response variable will be obtained from a value of 110 as the explanatory variable. What is the predicted response value? y = (Report answer accurate to one decimal place.)
You run a regression analysis on a bivariate set of data (n = 40). With 7 = 54.4 and y = 25.7, you obtain the regression equation y = 1.034x + 54.019 with a correlation coefficient of r = 0.628. You want to predict what value (on average) for the response variable will be obtained from a value of 40 Is the explanatory variable. What is the predicted response value? y -
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 38.6 51.4 55.1 86.4 32.9 33.6 24.4 23.8 27 56.6 22.5 26.6 15 34.8 23.2 28.2 22.9 24.4 14 -6.5 40.2 81.2 36.4 48 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 4.4 on the response variable. What is...
ou run a regression analysis on a bivariate set of data (n=65n=65). You obtain the regression equationy=−1.915x+−54.061y=-1.915x+-54.061with a correlation coefficient of r=−0.626r=-0.626 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 30 on the response variable.What is the predicted explanatory value?x = _______
PLEASE SHOW ME ON TI84 You run a regression analysis on a bivariate set of data (n = 108). With z = 27.5 and у = 67.4, you obtain the regression equation y 0.488z 33.947 with a correlation coefficient of r = 0.076. You want to predict what value (on average) for the response variable will be obtained from a value of 150 as the explanatory variable. What is the predicted response value? (Report answer accurate to one decimal place.)
You run a regression analysis on a bivariate set of data (n=105n=105). With ¯x=76.2x¯=76.2 and ¯y=78.6y¯=78.6, you obtain the regression equation y=0.507x−31.989y=0.507x-31.989 with a correlation coefficient of r=0.462r=0.462. You want to predict what value (on average) for the response variable will be obtained from a value of 160 as the explanatory variable. What is the predicted response value? y =
14) Fill in the Blank. You run a regression analysis on a bivariate set of data (n=25). With x(x-bar) -58.2 and "y=42.5 (y- bar), you obtain the regression equation yly-hat) - 3.111x-23.245 with a correlation coefficient of r=-0.095. You want to predict what value (on average) for the response variable will be obtained from a value of 50 as the explanatory variable. What is the best predicted response value, ya = ? Report answer accurate to one decimal place. Fill...
You run a regression analysis on a bivariate set of data (n=81n=81). With ¯x=33.6x¯=33.6 and ¯y=80.6y¯=80.6, you obtain the regression equation y=−2.744x+43.641y=-2.744x+43.641 with a correlation coefficient of r=−0.045r=-0.045. You want to predict what value (on average) for the response variable will be obtained from a value of 130 as the explanatory variable. What is the predicted response value? y =