Question

4. Calculate the equilibrium constant in terms of concentration (K) for the following reaction when at equilibrium, there are 0.0406 mol of CH,OH, 0.170 mol of CO, and 0.302 mol of H2 in a 2.00 L container. (Hint: you will have to calculate equilibrium concentrations using moles and volume.) COⓇ) + 2 H20) = CH3OH)

Answer 1

Equilibrium constant (k_{​​​​​​c}) = 18.624

first we... liven reaction corg) + 2H2(g) ² chyon (g) & find the equilibrium concentration of each reacto and product. 1. mіч». Оen cenko e сце, о- очо6 он - 0-030 м eauilibrium on of cholz 2L Equilibrium concentration of M₂ = 0.302 mol = 0.151 M 2L Equilibrium concentration of co - 0.170 mel. 0.08594 for, a general reaction ang) + bBlg) < <C(g) + d 0(5) - Equilibrium constant = kc = [ egʻojd - [A]a[B]} so, for equation 0, Equilibrium constant Expression is kez [44301] [co] [12]² substitute the values of concentration 0.0203_ - 0.0203 ibrium constant k = 0.151 X 0.1S) X 0.007225 = 0.0203 0.00109 -=18.624 I Equilibrium constant = ke = 18.624)