Question

A block of massm₁ = 1.5 kg initially moving to the right with a speed of 2.6 m/s on a frictionless, horizontal track collides with a spring attached to a second block of mass m₂ = 3.7 kg initiall at rest. The spring constant is 569N/m.

(a) Find the maximum spring compression in this case.
x =  m

What will be the individual velocities of the two masses (v₁ and v₂) after the spring extended fully again? (That is, when the two masses separate from each other after the collision is complete.)

Use the relations implied by the having the same total kinetic energy and same total momentum at the end to solve this problem.

v1	=	m/s to the left
v2	=	m/s to the right

Answer 1

The velocities of the two blocks after the collision.

(1.5 * 5) + (3.7 * -2.7) = 1.5 v1' + 3.7 v2'

1.5 v₁' + 3.7 v₂' = - 2.49

5 - (-2.7) = v2' - v1'

2.3 = v₂' - v₁'

v₁' = -5.96, v₂' = 1.74