Given Data
mass m = 9 kg
coefficient of static friction u = 0.5
Angle theta = 30 deg
down force (weight) = friction force + Fv
Where friction force = coefficient of friction times the normal
force (or the normal to the wall component of the applied force
F).
So we have
Fv = Fcos(30)
W = uFsin(30) + Fcos(30)
m*g = uFsin(30) + Fcos(30)
m*g = F*[usin(30) + cos(30)]
F = m*g / (usin(30) + cos(30))
F = 9*9.81 / [0.50*sin(30) + cos(30)]
F = 88.3 / [1.116]
F = 79.11 N
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