Homework Answers
a] Force F = q v x B
Force will be into the page
b] F = qvB sin theta = 0.05*1000*0.001* sin (90 - 30) degree = 0.0433 N
c] acceleration a = F/m = 0.0433/0.001 = 43.3 m/s^2
d] No, direction of velocity changes because of magnetic force, and the changed velocity will cause change in magnetic force and thus acceleration also changes.
It will be a helicalpath.
A particle with charge of 2 (HC), mass of 2x10-20 (kg) and velocity of 200 (m/s)...
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A particle with charge of 2 (HC), mass of 2x10-20 (kg) and velocity of 200 (m/s)...
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v
= (5î + 5ĵ − ) m/s
through a region where both a uniform magnetic field and a uniform
electric field exist.
(a)
Calculate the total force on the moving particle, taking
B
= (5î + 2ĵ + ) T
and
E
= (3î − ĵ − 2) V/m.
(Give your answers in N for each component.)
Fx= NFy=
NFz= N
(b)
What angle does...
Problem 1: A car of mass 1000 kg moves at a constant speed of 20 m/s...
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please do all part a,b,c,d A particle with charge of 2 (HC), mass of 2X10-20 (kg)...
please do all part a,b,c,d
A particle with charge of 2 (HC), mass of 2X10-20 (kg) and velocity of 200(m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01x10-S(N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and magnetic field, using...
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A particle with charge of 2 (HC), mass of 2x10-20 (kg) and velocity of 200 (m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01x10-S (N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and magnetic field, using RHR-1 D) In...
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A particle with charge of +5.0 X 10^-4 C, and mass of 2.0X10^-9 kg moves at 2.0X10^3 m/s in the +x direction. It enters a uniform magnetic field of 0.20 T that?s points in the +y direction. (a) What will be magnitude and direction of the force on this charged particle due to the magnetic field? Suppose magnetic field exists over a large area, large enough to trap the charged particle and continues to gyrate in the same circle. (b)...
A particle with positive charge q = 4.01 10-18 C moves with a velocity
v
= (5î + 5ĵ − ) m/s
through a region where both a uniform magnetic field and a uniform
electric field exist.
(a)
Calculate the total force on the moving particle, taking
B
= (5î + 2ĵ + ) T
and
E
= (3î − ĵ − 2) V/m.
(Give your answers in N for each component.)
Fx= NFy=
NFz= N
(b)
What angle does...
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A particle with charge of 2 (HC), mass of 2X10-20 (kg) and velocity of 200(m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01x10-S(N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and magnetic field, using...
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