∆Tf = i × Kb × m
m = molality = mol/ mass of solvent (Kg)
m = mol/0.168
Mass of solvent (water) = v × d
= 168×1= 168 g = 0.168 kg
0 - (-1.29) = 1×1.86× mole/0.168
Mole = 0.116 mol
Molar mass = mass/ mole
= 197×10-3 g/.116
= 1.69 g/mol
8. (8 pts) For a solution that contains 197 mg of a nonelectrolyte and 168 mL...
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