Question

In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with garlic in a processed tablet

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Answer #1

Solution:

Confidence interval for Population mean is given as below:

Confidence interval = Xbar ± t*S/sqrt(n)

We are given

Xbar = 4.8

S = 16.6

n = 43

df = n – 1 = 42

Confidence level = 95%

Critical t value = 2.0181

(by using t-table or excel)

Confidence interval = Xbar ± t*S/sqrt(n)

Confidence interval = 4.8 ± 2.0181*16.6/sqrt(43)

Confidence interval = 4.8 ± 2.0181*2.531476268

Confidence interval = 4.8 ± 5.1087

Lower limit = 4.8 - 5.1087 = -0.31

Upper limit = 4.8 + 5.1087 = 9.91

-0.31 mg/dL < µ < 9.91 mg/dL

What does the confidence interval suggest about the effectiveness of the treatment?

A. The confidence interval limits contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels.

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