Derive equations for finding the following, during the titration of a weak base using a strong acid;
1. Initial pH
2. pH at any given point before equivalence point
3. pH at equivalence point
4. pH at any given point after equivalence point
let the weak base be BOH
BOH ------------> B+ + OH-
Kb = [B+][OH-]/[BOH]
[OH-] = Kb[BOH]/[B+]
Kw = [OH-][H+]
[H+ ] = Kw / [OH-] = Kw/Kb[BOH]/[B+]
pH = 14 - log(Kb[BOH]/[B+])
2) At any point before equivalence point
its a basic buffer solution
Kb = [B+]salt[OH-]/[BOH]base
[OH-] = Kb[BOH]base/[B+]salt
taking negative log
pOH = pkb + log([B+]salt/[BOH]base)
pH = 14 - pOH = 14- {pkb + log([B+]salt/[BOH]base)}
3) At equivalence ,
its a case of Salt Hydrolsis so
pH = 7 -1/2pkb - logc
Derive equations for finding the following, during the titration of a weak base using a strong...
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