Question

Example Problem: 1. What is the percentage of total acid expressed as acetic acid (HC2H302) in a sample of vinegar if 3.000g

0 0
Add a comment Improve this question Transcribed image text
Answer #1

First Molar mass 204.22 Convert Normality to number of moles of KHP = 204. 22 g/mol molar mass Equivalent of Hydrogen atoms V

Add a comment
Know the answer?
Add Answer to:
Example Problem: 1. What is the percentage of total acid expressed as acetic acid (HC2H302) in...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A titration of 25.00 mL of an acetic acid solution with 0.1220 M NaOH solution starts...

    A titration of 25.00 mL of an acetic acid solution with 0.1220 M NaOH solution starts at a burette reading for NaOH of 0.17 mL. The phenolphthalein indicator turns light pink in the acid solution for over 30 seconds at a burette reading of 36.32 mL. The volume of NaOH used to neutralize the acid is _______ mL.

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Date: Anme: instructor's Initials: Lab Section: Determination of mination of Acetic Acid in Vinegar by Titration...

    Date: Anme: instructor's Initials: Lab Section: Determination of mination of Acetic Acid in Vinegar by Titration Pre-lab due at the beginning of Week 1 ced reaction of the neutralization of KHP and sodium hydroxide is: The balanced reaction a NaOH (aa) + KHC H4O4 (aa) - HO + NaC HOA Bu analogy, write the balanced reaction for the neutralization of acetic acid (HC2H302) by sodium hydroxide. 2. If the titration of 0.8094 g of 100% pure KHP requires 40.25 mL...

  • 4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted...

    4. Vinegar is a solution of acetic acid. Acetic acid has a 1:1 ratio when reacted with NaOH. a. Suppose that the molarity of acetic acid in vinegar is 0.5 M, how many grams of acetic acid are present in the 5 ml of vinegar solution used in the titration? (molar mass of acetic acid = 60 g/mol). b. If vinegar has a density of 1.01 g/mol. Calculate the % of acetic acid in vinegar by mass. 5. 50 ml...

  • Standardization of NaOH solution experiment: A 0.75 g sample of pure acid KHP was titrated to...

    Standardization of NaOH solution experiment: A 0.75 g sample of pure acid KHP was titrated to phenolphthalein endpoint using 45.34 ml NaOH of unknown concentration. The formula weight of pure KHP is 204.22g/mol. Write the chemical equation for the neutralization reaction, indicate the color change of the indicator at the endpoint, and calculate molarity of the NaOH solution. Show your work. 1. Chemical equation ------------- 2. Endpoint color change ---- 3. NaOH molarity --------- Determine percent purity of impure KHP...

  • What information then do you need? This is Chem 2 and not Org Chem. Titration of...

    What information then do you need? This is Chem 2 and not Org Chem. Titration of Vinegar Lab Report 1 /25 pts) Name: Part 1: Data and Calculations mass KHC.H.O. - 4.0744 g Molecular Weight potassium hydrogen phthalate KHC.H. - [1 pt) #moles KHP = [0.5 pts) Volume of solution = 250 ml_ L10.5 pts] Concentration of KHP = Mop = _M (1 pt) Volume of KHP Solution to be titrated mL = [1 pt) #mols of KHP to be...

  • Calculate the moles of acetic acid, molarity of the vinegar solution, and mass %. of acetic...

    Calculate the moles of acetic acid, molarity of the vinegar solution, and mass %. of acetic acid in the vinegar using the average of three good trials used to titrate 5.00 mL of the vinegar. You may assume that the density of your vinegar sample is 1.01 g mL^-1. Drain off unused NaOH solution into a clean container and place it into a designated container. Wash the buret two times with regular tap water, then rinse with deionized water, and...

  • A student is trying to determine the concentration of an acetic acid (HC2H302) solution. They place...

    A student is trying to determine the concentration of an acetic acid (HC2H302) solution. They place 5.00 mL of it in a flask and titrate it with a 0.150 M NaOH solution. At the endpoint of the titration, they find that they have used 19.27 mL of the NaOH solution. Based on this information answer the following questions. a) How many moles of NaOH are used to reach the endpoint? moles NaOH b) How many moles of acetic acid were...

  • QUESTION 3 A solution of acetic acid, HC2H302, a weak monoprotic acid, was standardized by titration...

    QUESTION 3 A solution of acetic acid, HC2H302, a weak monoprotic acid, was standardized by titration with 0.1660 M NaOH solution. If 20.59 mL of the NaOH were required to neutralize completely 18.23 ml of the acetic acid solution, what is the molarity o of the acetic acid solution?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT